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Sergio039 [100]
1 year ago
14

How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?

Chemistry
2 answers:
velikii [3]1 year ago
8 0

Answer : The number of moles of hydrogen gas is, 0.033 mole

Explanation : Given,

Moles of sodium = 0.066 mole

The balanced chemical reaction will be,

2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq)+H_2(g)

From the balanced chemical reaction, we conclude that 2 moles of sodium  react with 2 moles of water to give 2 moles of sodium hydroxide and 1 mole of hydrogen has as a product.

As, 2 moles of sodium react to give 1 mole of hydrogen gas

So, 0.066 mole of sodium react to give \frac{1}{2}\times 0.066=0.033 moles of hydrogen gas

Therefore, the number of moles of hydrogen gas is, 0.033 mole

SVEN [57.7K]1 year ago
6 0
Base on my research the complete reaction of hydrogen and sodium are form by this equation  2Na + 2H2O = 2NaOH +H2 If we base from this equation it shows you already the ratio of the moles of the product and reactants taking part in the reaction

1 mole of Na r/w 1 mole of water to produce .5 mole of Hydrogen 

Therefore, .066 mole of Na produces .033 moles of H2
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6 0
2 years ago
The electron configuration of an element is 1s22s22p4. Describe what most likely happens when two atoms of this element move tow
ahrayia [7]

When two atoms of this element move towards each other, they will combine in a covalent bond to form a diatomic molecule.

Looking at the electron configuration of the atoms; 1s2 2s2 2p4, we can see that these are atoms of elements in group 16. The elements in group 16 has a general outer electronic configuration of ns2np4. They have a valency of 2.

When two atoms of this element approach each other, they will combine in a covalent bond to form a compound. If this element is depicted as X, the compound formed is X2.

Learn more: brainly.com/question/1527403

5 0
1 year ago
How many moles are contained in 3.131 × 1024 particles?
Mnenie [13.5K]
One mole contains 6.02×10²³
If x mole contains 3.131×10²⁴

x = 3.131×10²⁴
-------------
6.02×10²³

x = 0.52×10²⁴¯²³

x = 0.52×10¹

x = 5.2moles....

Hope this helped...?
5 0
1 year ago
A sample of pure lithium chloride contains 16% lithium by mass. What is the % lithium by mass in a sample of pure lithium carbon
Anna35 [415]

Answer:

Percentage lithium by mass in Lithium carbonate sample = 19.0%

Explanation:

Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g

Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g

Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%

Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g

Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%

Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g

mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g

Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%

Percentage lithium by mass in Lithium carbonate sample = 19.0%

3 0
1 year ago
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu
Pani-rosa [81]

83.3 mL

Explanation:

M_{i} = 3M

V_{i} = 50mL

M_{f} = 1.80M

Unknown:

V_{f} = ?

Solution:

To solve this problem we must understand that the initial and final number of moles remains the same.

  Number of moles = molarity x volume

Molarity x volume of initial solution = Molarity x volume of final solution

 Therefore:

   M_{i}  x  V_{i}     = M_{f} x   V_{f}

M is the molarity

V is the volume

i = initial state

f = final state

    input the parameters;

  3 x 50 = 1.8 x V_{f}

      V_{f} = 83.3 mL

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

8 0
1 year ago
Read 2 more answers
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