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nignag [31]
2 years ago
9

A flask that can hold 158 g of water at 4oc can hold only 127 g of ethanol at the same temperature. what is the density of ethan

ol?
Chemistry
2 answers:
Citrus2011 [14]2 years ago
7 0

Answer:

0.8037 g/mL is the density of ethanol.

Explanation:

Mass of the water = m = 158 g

Volume of the water in the flask= V

Density of the water = d= 1.00 g/mL

\density=\frac{Mass}{Volume}

1.00 g/mL=\frac{m}{V}=\frac{158 g}{V}

V = 158.00 mL

Now, mass of an ethanol hold by flask, M = 127 g

Volume of the flask = V = 158.00 mL

Density of the ethanol =D

D=\frac{M}{V}=\frac{127 g}{158.00 mL}=0.8037 g/mL

0.8037 g/mL is the density of ethanol.

Elza [17]2 years ago
3 0

<em>Answer:</em>

  • The density of ethanol will be 0.80 g/ml.

<em>Explanation:</em>

   As we know, density of water is 1 g/ml which show that 158 g of water contain 158 ml of water.

                        d = m/v = 258/258 = 1 g/ml

So there will be same volume for ethanol

                  density of ethanol = 127/158 = 0.80 g/ml

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the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

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So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

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the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

5 0
2 years ago
How many ml of a 14.0 m nh3 stock solution are needed to prepare 200 ml of a 4.20 m dilute nh3 solution? hints how many ml of a
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5 0
2 years ago
The Keq for the equilibrium below is 5.4 × 1013 at 480.0 °C. 2NO (g) + O2 (g) 2NO2 (g) What is the value of Keq at this temperat
kodGreya [7K]

<u>Answer:</u> The equilibrium constant for NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g) equation is 1.36\times 10^{-7}

<u>Explanation:</u>

The given chemical equation follows:

2NO(g)+O_2(g)\rightleftharpoons 2NO_2(g)

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The value of equilibrium constant for the above equation will be:

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5 0
1 year ago
N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t
son4ous [18]

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So, we find the the remaining (N_{2}) will be 0.6 and

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8 0
2 years ago
Read 2 more answers
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crimeas [40]
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