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nignag [31]
2 years ago
9

A flask that can hold 158 g of water at 4oc can hold only 127 g of ethanol at the same temperature. what is the density of ethan

ol?
Chemistry
2 answers:
Citrus2011 [14]2 years ago
7 0

Answer:

0.8037 g/mL is the density of ethanol.

Explanation:

Mass of the water = m = 158 g

Volume of the water in the flask= V

Density of the water = d= 1.00 g/mL

\density=\frac{Mass}{Volume}

1.00 g/mL=\frac{m}{V}=\frac{158 g}{V}

V = 158.00 mL

Now, mass of an ethanol hold by flask, M = 127 g

Volume of the flask = V = 158.00 mL

Density of the ethanol =D

D=\frac{M}{V}=\frac{127 g}{158.00 mL}=0.8037 g/mL

0.8037 g/mL is the density of ethanol.

Elza [17]2 years ago
3 0

<em>Answer:</em>

  • The density of ethanol will be 0.80 g/ml.

<em>Explanation:</em>

   As we know, density of water is 1 g/ml which show that 158 g of water contain 158 ml of water.

                        d = m/v = 258/258 = 1 g/ml

So there will be same volume for ethanol

                  density of ethanol = 127/158 = 0.80 g/ml

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Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group:  R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

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Consider the solutions, 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3 and 0.04 m CaCl2. Which has (i) the highest osmotic pressure, (ii
Lana71 [14]

Answer:

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

iii) highest boiling point : CaCl2

Explanation:

The colligative properties depend upon the number of solute particles in a solution.

The following four are the colligative properties:

a) osmotic pressure : more the concentration of the solute, more the osmotic pressure

b) vapor pressure: more the concentration of the solute, lesser the vapor pressure.

c) elevation in boiling point: more the concentration of the solute, more the boiling point.

d) depression in freezing point: more the concentration of the solute, lesser the freezing point.

the number of particle produced by urea = 1

the number of particle produced by AgNO3 = 2

the number of particle produced by CaCl2 = 3

As concentrations are same, CaCl2 will have more number of solute particles and urea will have least

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

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For this problem, we use the formula for sensible heat which is written below:

Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference

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Suppose there is 0.63 g of HNO3 per 100 mL of a particular solution. What is the concentration of the HNO3 solution in moles per
Vadim26 [7]

Answer:

There are 0.09996826 moles per liter of the solution.

Explanation:

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Convert mL to L and place under moles (mol/L)

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This is term used in anatomy.

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