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nignag [31]
2 years ago
9

A flask that can hold 158 g of water at 4oc can hold only 127 g of ethanol at the same temperature. what is the density of ethan

ol?
Chemistry
2 answers:
Citrus2011 [14]2 years ago
7 0

Answer:

0.8037 g/mL is the density of ethanol.

Explanation:

Mass of the water = m = 158 g

Volume of the water in the flask= V

Density of the water = d= 1.00 g/mL

\density=\frac{Mass}{Volume}

1.00 g/mL=\frac{m}{V}=\frac{158 g}{V}

V = 158.00 mL

Now, mass of an ethanol hold by flask, M = 127 g

Volume of the flask = V = 158.00 mL

Density of the ethanol =D

D=\frac{M}{V}=\frac{127 g}{158.00 mL}=0.8037 g/mL

0.8037 g/mL is the density of ethanol.

Elza [17]2 years ago
3 0

<em>Answer:</em>

  • The density of ethanol will be 0.80 g/ml.

<em>Explanation:</em>

   As we know, density of water is 1 g/ml which show that 158 g of water contain 158 ml of water.

                        d = m/v = 258/258 = 1 g/ml

So there will be same volume for ethanol

                  density of ethanol = 127/158 = 0.80 g/ml

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2 years ago
A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100.°c (reported to three significant
VLD [36.1K]

Explanation:

According to Charle's law, at constant pressure the volume of an ideal gas is directly proportional to the temperature.

That is,             Volume \propto Temperature

Hence, it is given that V_{1} is 3.50 liters, T_{1} is 20 degree celsius, and T_{2} is 100 degree celsius.

Therefore, calculate V_{2} as follows.

                           \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

                           \frac{3.50 liter}{20^{o}C} = \frac{V_{2}}{100^{o}C}

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6 0
2 years ago
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Two students titrated a 25.0 mL aliquot of pear juice with 0.107 M NaOH to the phenolphthalein end point. The initial buret read
Olin [163]

Answer:

0.363g citric acid

Explanation:

Sodium hydroxide (NaOH) reacts with acids, thus:

NaOH + H⁺ → H₂O + Na⁺

The volume of titration is:

18.39mL - 0.73mL = 17.66mL

Moles of this volume in 0.107M NaOH are:

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As molar mass of citric acid is 192.124g/mol:, Mass of citric acid is:

0.00189mol citric acid × (192.124g / mol) = <em>0.363g citric acid</em>

I hope it helps!

6 0
2 years ago
When uranium-235 atoms undergo fission, ________ is/are produced?
elena-s [515]
Smaller atoms ; free neutrons and energy
8 0
2 years ago
6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021
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Answer:

The total amount of Au is $ 2.0\times10^{24}

Explanation:

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We need to calculate the volume in ml

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Using given data

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The total amount of the Au Will be

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