From the chemical formula of sulfuric acid, we can see the molar ratio:
H : S : O
2 : 1 : 4
Now, we convert the mass of hydrogen given into the moles of hydrogen. This is done using
Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27
Therefore, the moles will be:
S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles
Now, the respective masses are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams
Answer:
0.363g citric acid
Explanation:
Sodium hydroxide (NaOH) reacts with acids, thus:
NaOH + H⁺ → H₂O + Na⁺
The volume of titration is:
18.39mL - 0.73mL = 17.66mL
Moles of this volume in 0.107M NaOH are:
0.01766L × (0.107 mol / L) = 0.00189mol NaOH ≡ mol citric acid<em> -Assuming the only acid in pear juice is citric acid-</em>
As molar mass of citric acid is 192.124g/mol:, Mass of citric acid is:
0.00189mol citric acid × (192.124g / mol) = <em>0.363g citric acid</em>
I hope it helps!
Answer : The normality of the solution is, 30.006 N
Explanation :
Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.
Mathematical expression of normality is:

or,

First we have to calculate the equivalent weight of solute.
Molar mass of solute
= 94.97 g/mole

Now we have to calculate the normality of solution.

Therefore, the normality of the solution is, 30.006 N
Answer:
The concentration is 0,2925M
Explanation:
We use the formula
C initial x V initial = C final x V final
11,7 M x 25 ml = C final x 1000 ml
C final= (11,7 M x 25 ml)/1000 ml = 0, 2925 M
(This formula applies to liquid solutions)
Find moles of MgSO4.7H2O
molar mass = 246
so moles = 32 / 246 = 0.13 moles.
When heated, all 7 H2O from 1 molecule will be gone.
total moles of H2O present = 7 x 0.13 = 0.91
mass of those H2O = 0.91 x 18 = 16.38g
so mass of anyhydrous MgSO4 remain = 32 - 16.38 = 15.62 g