There are several process in the nature, which keeps water cycling between them. By Precipitation, Earth's sphere gets water which we use in several ways, and by evaporation & sublimation, it goes back to upper spheres of the Earth's atmosphere and cycle happens again & again.
Hope this helps!
Answer: pH=12.69
Explanation:



Initial 0.12 0 0
Eqm 0.12-x x x
![K_a=\frac{[H^+][F^-]}{[HF]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BF%5E-%5D%7D%7B%5BHF%5D%7D)
(neglecting small value of x in comparison to 0.12)

Moles of 



0.06 moles of NaOH will give 0.06 moles of ![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D)
Now
moles of
will be neutralized by
moles of
and
moles of
will be left.
Molarity of 
![pOH=-\log[OH^-]=-\log[0.049]=1.31](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D%3D-%5Clog%5B0.049%5D%3D1.31)
pH = 14 - pOH= 14 - 1.31 = 12.69
Answer:
C. effusion because there is a movement of a gas through a small opening into a larger volume
Explanation:
Effusion makes fluid/gas molecules move to the container with less pressure or larger volume. In diffusion, the movement should work two ways even though one side might receive more. But in effusion, the movement is rather one way.
This case shows how effusion work because its not the concentration that makes the balls moving to the bottom part of the container. No ball moving from bottom container to top either.
Answer:
92.65256 cm^3
Explanation:
To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.
Answer:
Volume of lithium atom is found to be 1.47 X 10⁻²⁹ m³
Explanation:
Let us consider the volume of atom as a sphere (but it is little complex than that). This volume is mathematically expressed as,
----------------------------------------------------------------------------------------(Eq. 1)
Here, R is the radius of lithium atom. The radius is given in picometers, so firstly let us convert it into meters


placing this value in Eq.1 the required result is achieved

V= 1.47 X 10⁻²⁹ m³