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Vikentia [17]
2 years ago
5

Nh4i(aq)+koh(aq)→ express your answer as a chemical equation. identify all of the phases in your answer.

Chemistry
2 answers:
tester [92]2 years ago
5 0
NH4I (aq)  +  KOH  (aq)  in   chemical   equation  gives

   NH4I (aq)  +  KOH (aq)   =  KI  (aq)  +  H2O(l)  +  NH3  (l)

Ki  is  in  aqueous  state  H2o   is  in   liquid  state  while  NH3  is  in  liquid  state

from  the  equation  above  1 mole of  NH4I (aq) react  with  1 mole of KOH(aq) to  form  1mole of KI(aq) ,  1mole of H2O(l)  and 1  Mole  of NH3(l)
Norma-Jean [14]2 years ago
4 0

Answer:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

Explanation:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

This is a reaction of aqueous ammonium iodide and aqueous potassium hydroxide to yield aqueous potassium iodide, gaseous ammonia and liquid water as shown above.

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Explain how interactions between Earth’s spheres keep water cycling between them
Elenna [48]
There are several process in the nature, which keeps water cycling between them. By Precipitation, Earth's sphere gets water which we use in several ways, and by evaporation & sublimation, it goes back to upper spheres of the Earth's atmosphere and cycle happens again & again.

Hope this helps!
3 0
2 years ago
A 600.0 mL sample of 0.20 MHF is titrated with 0.10 MNaOH. Determine the pH of the solution after the addition of 600.0 mL of Na
Leona [35]

Answer: pH=12.69

Explanation:

{\text{Moles of HF}=Molarity\times {\text{Volume of solution in liters}}

{\text{Moles of HF}=0.20M\times 0.6L=0.12 moles

HF\rightarrow H^++F^-

Initial 0.12               0       0

Eqm   0.12-x           x        x

K_a=\frac{[H^+][F^-]}{[HF]}

3.5\times 10^{-4}=\frac{x^2}{0.12-x}  

(neglecting small value of x in comparison to 0.12)

x=4.2\times 10^{-5}

Moles of H^+=4.2\times 10^{-5}

NaOH\rightarrow Na^++OH^-

{\text{Molesof NaOH}}=Molarity\times {\text{Volume of solution in liters}}

{\text{Moles of NaOH}}=0.10M\times 0.6L=0.06 moles

0.06 moles of NaOH will give 0.06 moles of [OH^-]

Now 4.2\times 10^{-5} moles of OH^- will be neutralized by 4.2\times 10^{-5} moles of H^+ and (0.06-4.2\times 10^{-5})=0.059 moles of OH^- will be left.

Molarity of OH^-=\frac{0.059moles}{1.2L}=0.049M

pOH=-\log[OH^-]=-\log[0.049]=1.31

pH = 14 - pOH= 14 - 1.31 = 12.69

5 0
2 years ago
The diagram shows the movement of particles from one end of the container to the opposite end of the container. A cylindrical co
trapecia [35]

Answer:

C. effusion because there is a movement of a gas through a small opening into a larger volume

Explanation:

Effusion makes fluid/gas molecules move to the container with less pressure or larger volume. In diffusion, the movement should work two ways even though one side might receive more. But in effusion, the movement is rather one way.

This case shows how effusion work because its not the concentration that makes the balls moving to the bottom part of the container. No ball moving from bottom container to top either.

3 0
2 years ago
Read 2 more answers
A deck of cards has dimensions 8.9cm x 5.72cm x 1.82 cm. What is the volume of the deck in cubic centimeters?
arsen [322]

Answer:

92.65256 cm^3

Explanation:

To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.

5 0
2 years ago
The metallic radius of a lithium atom is 152 pm. What is the volume of a lithium atom in cubic meters?
Anuta_ua [19.1K]

Answer:

Volume of lithium atom is found to be 1.47 X 10⁻²⁹ m³

Explanation:

Let us consider the volume of atom as a sphere (but it is little complex than that). This volume is mathematically expressed as,

V=\frac{4}{3}\pi  R^{3}----------------------------------------------------------------------------------------(Eq. 1)

Here, R is the radius of lithium atom. The radius is given in picometers, so firstly let us convert it into meters

R=(152pm )(1X10^{-12}\frac{m}{pm})

R = 1.52 X 10^{-10}m

placing this value in Eq.1 the required result is achieved

V=\frac{4}{3}\pi  {1.52X10^{-10}}^{3}

V= 1.47 X 10⁻²⁹ m³

8 0
2 years ago
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