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Bumek [7]
2 years ago
11

A 141mg sample was placed on a watch glass that has a mass of 9.203g. what is the mass of the watch glass and sample in grams?

Chemistry
1 answer:
Volgvan2 years ago
8 0

Given the mass of sample placed on the watch glass = 141 mg

Converting mass of the sample from mg to g:

141 mg * \frac{1 g}{1000 mg} =0.141 g

Mass of watch glass = 9.203 g

So, the total mass of watch glass and the sample = 9.203 g +0.141 g = 9.344 g

Therefore, the mass of the watch glass and the sample in grams is 9.344 g

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Calculate the hydrogen ion concentration in a solution of fruit juice having a pH of 4.25.
Airida [17]

Answer:

<h3>The answer is option B</h3>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ H+ ]

To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]

From the question

pH = 4.25

So we have

4.25 = - log [ H+ ]

<u>Find the antilog of both sides</u>

That's

<h3>[ H+ ] =  {10}^{ - 4.25}</h3>

We have the final answer as

<h2>[ H+ ] = 5.6 \times  {10}^{ - 5}  \: M</h2>

Hope this helps you

3 0
2 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
JulijaS [17]

Answer : The correct option is, 30.9^oC

Explanation :

Formula used :

q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

q = heat released = 24 KJ

m = mass of bomb calorimeter = 1.30 Kg

c = specific heat = 3.41J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25.5^oC

Now put all the given values in the above formula, we get  the final temperature of the calorimeter.

q=m\times c\times (T_{final}-T_{initial})

24KJ=1.30Kg\times 3.41J/g^oC\times (T_{final}-25.5)^oC

T_{final}=30.9^oC

Therefore, the final temperature of the calorimeter is, 30.9^oC

5 0
2 years ago
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Looking at this equation P= (pa*pb)/ (pa+(pb-pa)) ya  where pa=vap press a and ya= vap composition a and P= total pressure,it relates vapor pressure mixture to vapor composition. This is derived using the combination of Dalton's and Raoult's laws.
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How many moles of nitrogen are in 3.7 moles of C8H11NO2?
Phoenix [80]
<h3>Answer:</h3>

               3.7 Moles of Nitrogen

<h3>Explanation:</h3>

                      On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;

8 Moles of Carbon

11 Moles of hydrogen

1 Mole of Nitrogen and

2 Moles of Oxygen respectively.

<u>Calculate Number of Moles of Nitrogen:</u>

As,

                   1 Mole of C₈H₁₁NO₂ contains  =  1 Mole of Nitrogen

So,

            3.7 Moles of C₈H₁₁NO₂ will contain  =  X Moles of Nitrogen

Solving for X,

                       X  =  (3.7 Moles × 1 Mole) ÷ 1 Mole

                       X  =  3.7 Moles of Nitrogen

4 0
2 years ago
Which term describes the maintenance of a steady internal state in the body?
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B, homeostasis. “Homeostasis is the state of steady internal, physical, and chemical conditions maintained by living systems.”
5 0
2 years ago
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