Well it breaks down into small parts
Answer:
- <em>The minimum number of photons that can be detected by the human eye is </em><u><em>6.03 × 10 ¹⁶</em></u><em> photons.</em>
Explanation:
The energy of one photon of light is related to the wavelength by the equation:
Where, E is the energy of one photon, h is the Planck's constant, c is the speed of light, and λ is the wavelength of the light.
You are given with <em>λ = 510 nm</em> (nanometers), which you must convert to m (meters), to use SI units ⇒ λ = 510 × 10⁻⁹ m.
The <em>physical constansts </em>needed are:
- Planck's constant, h = 6.63 × 10⁻³⁴ J.s
- Speed of light, in vacuum, c = 3.0 × 10⁻⁸ m/s
Now you can substitute in the formula can compute for the value of E:
- E = 6.63×10⁻³⁴ J.s × 3.0 × 10⁻⁸ m/s / (510×10⁻⁹ m) = 0.039 × 10⁻³³ J
Since, that is the energy of one photon of green light, to calculate the number of photons that can be detected by the human eye, you need to divide the amounf of <em>energy the human eye is able to detect, 2.35 × 10⁻¹⁸ J , </em>by the energy of a photon:
- number of photons = 2.35×10 ⁻¹⁸J / 0.039 × 10⁻³³ J/ photon
- number of photons = 60.3 × 10¹⁵ photons = 6.03 × 10¹⁶photons
Answer:
2) The volume of an underwater bubble increases as it rises and the pressure decreases
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Answer: 36.9 g
Explanation:
P4 + 5O2 = P4O10 Balanced equation
moles P4 present = 23.9 g x 1 mole/123.88 g = 0.193 moles
moles O2 present = 20.8 g x 1 mol/32 g = 0.65 moles O2
From balanced equation, mole ratio O2 : P4 is 5:1. Is 0.65 moles O2 5x 0.193 moles? NO. You don't have enough O2.
O2 is limiting in this reaction.
theoretical moles of P4O10 = 0.65 moles O2 x 1 mole P4O10/5 moles O2 = 0.13 moles P4O10
mass of P4O10 produced = 0.13 moles x 283.9 g = 36.9 g
<span>A piece of sodium metal can be described as a soft silvery white metal that is highly reactive and can sometimes cause explosions. This is the reason why it doesn't occur naturally as an isolated metal. Instead, different sodium containing compounds undergo different processes to isolate the sodium metal.</span>
