Ask question

Ask question

All categories

1 year ago

11

If an ionic compound were composed of a4+ and b−, which unit cell structure would give a neutral compound?

1 answer:

Ymorist [56]1 year ago

4 0

<span>biological reactions that happen within cells while reducing the complex interactions found in a whole cell. Eukaryotic and prokaryotic cells have been used for creation of these simplified environments[1]. Subcellular fractions can be isolated by ultracentrifugation to provide molecular machinery that can be used in reactions in the absence of many of the other cellular components. Cell-free biosystems can be prepared by mixing a number of purified enzymes and coenzymes. Cell-free biosystems are proposed as a new low-cost biomanufacturing platform compared to microbial fermentation used for thousands of years. Cell-free biosystems have several advantages suitable in industrial applications</span>

You might be interested in

To burn 1 molecule of C5H12 to form CO2 and H2O (complete combustion), how many molecules of O2 are required?

viva [34]

C5H12 + 8 O2 → 5 CO2 + 6 H2O

8 molecules of O2 are required.

5 0

1 year ago

Read 2 more answers

Identify the effects of electrical forces and the role electrical forces play in the formation of ionic bonds by completing the

uysha [10]

Hey Queens!

1) repel

2) attract

3) attract

7 0

1 year ago

Read 2 more answers

A solution that contains 55.0 g of ascorbic acid (vitamin C) in 250.0 g of water freezes at –2.34°C.

Ksju [112]

Answer:

174.8 g/m is the molar mass of the solute

Explanation:

We must apply colligative property of freezing point depression.

ΔT = Kf . m . i

ΔT = T° freezing pure solvent - T° freezing solution (0° - (-2.34°C) = 2.34°C

Kf = Fussion constant for water, 1.86 °C/m

As ascorbic acid is an organic compound, we assume that is non electrolytic, so i = 1

2.34°C = 1.86°C/m . m

2.34°C / 1.86 m/°C = 1.26 m

This value means the moles of vitamin C, in 1000 g of solvent

We weighed the solute in 250 g of solvent, so let's calculate the moles of vitamin C.

1000 g ___ 1.26 moles

In 250 g ___ (250 . 1.26)/1000 = 0.314 moles

This are the moles of 55 g of ascorbic acid, so the molar mass, will be:

grams / mol ⇒ 55 g/0.314 m = 174.8 g/m

3 0

1 year ago

Calculate the mass in grams of each of the following amounts: 1.002 mol of chromium 4.08 x 10-8 mol of neon

Pepsi [2]

Answer:

$Mass_{chromium}=52.1\ g$

$Mass_{neon}=8.23\times 10^{-7}\ g$

Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

Molar mass of chromium = 51.9961 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1.002\ mol= \frac{Mass}{51.9961\ g/mol}$

$Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g$

<u>Calculation of the mass of neon as:- </u>

Moles = $4.08\times 10^{-8}$ moles

Molar mass of neon = 20.1797 g/mol

Thus,

$1.002\ mol= \frac{Mass}{20.1797\ g/mol}$

$Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g$

6 0

2 years ago

How many particles would be found in a 1.224 g sample of K2O

lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0

2 years ago

Read 2 more answers