Explanation:
The given data is as follows.
= 253.4 nm =
(as 1 nm =
)
= 5,
= ?
Relation between energy and wavelength is as follows.
E = 
= 
=
J
= 
Hence, energy released is
.
Also, we known that change in energy will be as follows.

where, Z = atomic number of the given element


0.02 + 0.04 = 
= 
= 4
Thus, we can conclude that the principal quantum number of the lower-energy state corresponding to this emission is n = 4.
Water typically exist in its gaseous state in the atmosphere. Fog contains droplets of liquid water suspended in the air. Thus to produce a fog, vapor in the air would undergo condensation with a state change from gas to liquid.
Intermolecular interactions between water molecules strengthen as the vapor condenses to produce a liquid. The condensation of vapor thus involves a production of energy. With all the extra intermolecular interactions, molecules in the fog would find it more difficult to move around and therefore see a decrease in their motion.
Answer:
Removal of Third Electron
Explanation:
a major jump is required to remove the third electron. In general, successive ionization energies always increase because each subsequent electron is being pulled away from an increasingly more positive ion.
Ionization energy increases from bottom to top within a group, and increases from left to right within a period.
The answer is D; Mercury-194
All of the others are not when I looked them up