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Goryan [66]
2 years ago
14

Both the esophagus and the small intestine are involved in the digestion of food. The esophagus squeezes food into the stomach b

y wave-like muscle contractions. Peptidase enzymes in the small intestine break food molecules into smaller molecules.
Which statement best describes changes to food during digestion?

A. The muscle contractions result in physical changes, while the action of the peptidase results in chemical changes.

B. The muscle contractions result in chemical changes, while the peptidase results in physical changes.

C. The muscle contractions and the action of the peptidase both result only in physical changes.

D. The muscle contractions and the action in the peptidase both result only in chemical changes.
Chemistry
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

The answer is: A

Explanation:

The wave-like contractions are to be considered a physical change as they do not take part in the breaking-down of the food. The peptidase is a chemical change because it is used to chemically break down the food to retrieve nutrients and such.

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Calculate the nuclear binding energy for 5525mn in megaelectronvolts per nucleon (mev/nucleon). express your answer numerically
VARVARA [1.3K]

Answer:

8.533 Mev/nucleon

Explanation:

The given elements is:- ^{55}_{25}Mn

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, the number of protons = 25

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

55 =  25 + Number of neutrons

Number of neutrons = 30

Mass of neutron = 1.008665 amu

Mass of proton = 1.007825 amu

Calculated mass = Number of protons*Mass of proton + Number of neutrons*Mass of neutron

Thus,  

Calculated mass = (25*1.007277 + 30*1.008665) amu = 55.441875 amu

Actual mass = 54.9380451 amu

Mass defect = Δm = |54.9380451 - 55.441875| amu = 0.5038299 amu

The conversion of amu to MeV is shown below as:-

1 amu = 931.5 MeV

So, Energy = 0.5038299*931.5 MeV= 469.317552 MeV

Total number of nucleons in the atoms = 55

<u>So, Energy = 469.317552/55 MeV/nucleon = 8.533 Mev/nucleon</u>

5 0
2 years ago
a gas sample is heated from -20.0 C to 57.0 C and the volume is increased from 2.00L to 4.50L. If the initial pressure is 0.109a
Andreas93 [3]
Idk what this is im not good at this 
7 0
2 years ago
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
The interior of a refrigerator has a volume of 0.600 m3. the temperature inside the refrigerator in 282 k, and the pressure is 1
Dafna11 [192]
In this instance we can use the ideal gas law equation to find the number of moles of gas inside the refrigerator 
PV = nRT
where 
P - pressure - 101 000 Pa
V - volume - 0.600 m³
n - number of moles
R - universal gas constant - 8.314 J/mol.K
T - temperature - 282 K
substituting these values in the equation 
101 000 Pa x 0.600 m³ = n x  8.314 J/mol.K x 282 K
n = 25.8 mol
there are 25.8 mol of the gas
to find the mass of gas
mass of gas = number of moles x molar mass of gas
mass = 25.8 mol x 29 g/mol  = 748.2 g
mass of gas present is 748.2 g 
6 0
2 years ago
Arrange the following in order of increasing boiling point: RbCl, CH3Cl, CH3OH, CH4. A. CH3OH &lt; CH4 &lt; CH3Cl &lt; RbCl B. R
rosijanka [135]

Answer:

E. CH₄ < CH₃Cl < CH₃OH < RbCl

Explanation:

The molecule with the stronger intermolecular forces will have the higher boiling point.

The order of strength of intermolecular forces (strongest first) is

  • Ion-Ion
  • Hydrogen bonding
  • Dipole-dipole
  • London dispersion

RbCl is a compound of a metal and a nonmetal. It is an ionic compound, so it has the highest boiling point.

CH₃Cl has a C-Cl polar covalent bond. It has dipole-dipole forces, so it has the second lowest boiling point.

CH₃OH has an O-H bond. It has hydrogen bonding, so it has the second highest boiling point.

CH₄ has nonpolar covalent C-H bonds. It has only nonpolar bonds, so the only attractive forces are London dispersion forces. It has the lowest boiling point.

Thus, the order of increasing boiling points is

CH₄ < CH₃Cl < CH₃OH < RbCl

4 0
2 years ago
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