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Goryan [66]
2 years ago
14

Both the esophagus and the small intestine are involved in the digestion of food. The esophagus squeezes food into the stomach b

y wave-like muscle contractions. Peptidase enzymes in the small intestine break food molecules into smaller molecules.
Which statement best describes changes to food during digestion?

A. The muscle contractions result in physical changes, while the action of the peptidase results in chemical changes.

B. The muscle contractions result in chemical changes, while the peptidase results in physical changes.

C. The muscle contractions and the action of the peptidase both result only in physical changes.

D. The muscle contractions and the action in the peptidase both result only in chemical changes.
Chemistry
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

The answer is: A

Explanation:

The wave-like contractions are to be considered a physical change as they do not take part in the breaking-down of the food. The peptidase is a chemical change because it is used to chemically break down the food to retrieve nutrients and such.

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<u>Answer:</u> The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

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The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

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We are given:

Mass of CO_2=0.3986g

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  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.3986 g of carbon dioxide, \frac{12}{44}\times 0.3986=0.1087g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.0578 g of water, \frac{2}{18}\times 0.0578=0.0066g of hydrogen will be contained.

To calculate the percentage composition of a substance in sample, we use the equation:

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Mass of sample = 0.1153 g

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\%\text{ composition of carbon}=\frac{0.1087g}{0.1153g}\times 100=94.27\%

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\%\text{ composition of hydrogen}=\frac{0.0066g}{0.1153g}\times 100=5.72\%

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