Answer:
Explanation:
Hello,
In this case, since calcium hydroxide a strong base, its dissociation will completely result in both calcium and hydroxyl ions:
Thus, the concentration of hydroxyl ions equals that of the calcium hydroxide, with which we could compute the pOH as shown below:
![pOH=-log([OH^-]}=-log(0.0012)\\\\pOH=2.92](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%7D%3D-log%280.0012%29%5C%5C%5C%5CpOH%3D2.92)
Now, the pH and the pOH are related by:
Hence, the pH finally results:
Best regards.
Answer:
81°C.
Explanation:
To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat released from water (Q = - 1200 J).
m is the mass of the water (m = 20.0 g).
c is the specific heat capacity of water (c of water = 4.186 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).
∵ Q = m.c.ΔT
∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).
(- 1200 J) = 83.72 final T - 7953.
∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.
<em>So, the right choice is: 81°C.</em>
Answer:
Density: Physical Property
Flammability: Chemical Property
Solubility In Water: Physical Property
Reactivity With Water: Chemical Property
Melting Pot: Physical Property
Color: Physical Property
Odor: Physical Property
Explanation:
:)
Answer is: volume of helium is 244.72 liters.
m(He) = 43.7 g.
n(He) = m(He) ÷ M(He).
n(He) = 43.7 g ÷ 4 g/mol.
n(He) = 10.925 mol.
V(He) = n(He) · n(He).
V(He) = 10.925 mol · 22.4 L/mol.
V(He) = 244.72 L.
Vm - molar volume at STP.
n - amount of substance.
Answer : The correct option is, 
Explanation :
Formula used :
where,
= heat released = 24 KJ
= mass of bomb calorimeter = 1.30 Kg
= specific heat = 
= final temperature = ?
= initial temperature = 
Now put all the given values in the above formula, we get the final temperature of the calorimeter.
Therefore, the final temperature of the calorimeter is,
