Answer:
40.3∘C
Explanation:
At planet B;
Water boils = 180∘C
Water freezes = 50∘C
In this planet the temperature difference = 180 - 50 = 130 compared to earth where the temperature difference is; 100 - 0 = 100
This means;
130 ∘C = 100 ∘C
x ∘C = 31 ∘C
x = 31 * 130 / 100
x = 40.3∘C
The amount of hydrogen chloride that can be made is 1064 g
Why?
The two reactions are:
2H₂O → 2H₂ + O₂ 75.3 % yield
H₂ + Cl₂ → 2HCl 69.8% yield
We have to apply a big conversion factor to go from grams of water (The limiting reactant), to grams of HCl, the final product. We have to be very careful with the coefficients and percentage yields!


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Answer:
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
Explanation:
Using Boyle's law
Given ,
V₁ = 3.6 L
V₂ = ?
P₁ = 1.0 atm
P₂ = 13.3 atm
Using above equation as:
<u>The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.</u>
Answer : The mole fraction of nitrogen will be 0.4615.
Explanation : When nitrogen (
)and hydrogen (
)are mixed, the mole ratio becomes 1 : 1.5,
Now we know that (
) is acting as a limiting agent.
So at the time of when 0.4 moles of (
) is been formed it requires 0.4 moles of (
) and 3.4 moles of (
)
So, we find the the remaining (
) will be 0.6 and
(
) will be 0.3 mole present in mixture.
So, the mole fraction of (
) becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615
Answer:
Explanation:
Oxidation no is equal to charge on each atomic ion. If it is increased , element is oxidised and if it is decreased , element is reduced .
2AgCl+Zn⟶2Ag+ZnCl2
Zinc is oxidised , Ag is reduced .
Ag⁺ converts to Ag . ( oxidation number is reduced ) so Ag is reduced.
Zn converts to Zn⁺² ( oxidation number is increased ) so Zn is oxidised .
4NH₃+3O₂⟶2N₂+6H₂O
oxidation number of nitrogen in ammonia is - 3
oxidation no of nitrogen in nitrogen is zero.
Oxidation no of nitrogen is increased so it is oxidised.
oxidation no of oxygen is zero in oxygen and its oxidation no in water is -2 . So oxidation no is reduced so oxidation is reduced.
Fe₂O₃+2Al⟶Al₂O₃+2Fe
oxidation no of Fe in Fe₂O₃ is + 3 and it is zero in Fe so iron is reduced.
oxidation no of Al in Al is zero and it is +3 in Al₂O₃ so it is oxidised .