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Nutka1998 [239]
2 years ago
15

Calcium hydroxide, Ca(OH)2, is used as a calcium nutritional supplement in some foods and beverages, such as orange juice. What

is the pH of a solution of 0.0012M calcium hydroxide at 25.0∘C?
Chemistry
1 answer:
RSB [31]2 years ago
4 0

Answer:

pH=11.08

Explanation:

Hello,

In this case, since calcium hydroxide a strong base, its dissociation will completely result in both calcium and hydroxyl ions:

Ca(OH)_2\rightarrow Ca^{2+}+OH^-

Thus, the concentration of hydroxyl ions equals that of the calcium hydroxide, with which we could compute the pOH as shown below:

pOH=-log([OH^-]}=-log(0.0012)\\\\pOH=2.92

Now, the pH and the pOH are related by:

pOH+pH=14

Hence, the pH finally results:

pH=14-pOH=14-2.92\\pH=11.08

Best regards.

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2 years ago
why does every human measurement have uncertainty associated with it? Why must we manage the uncertainty during calculations?
dimulka [17.4K]
Because there are many numbers of the human measurement . we must manage the uncertainly doing calculations because we can know what we are calculating.
3 0
2 years ago
What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0
2 years ago
Jill is doing an experiment on the movement of pill bugs. She will place the pill bugs on flat surfaces covered with diffirent m
Ostrovityanka [42]

Answer:D

Explanation:

6 0
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how do i get the bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH₃CH₂CH₃) molecules is
stiv31 [10]

Answer:

2877kJ/mol

Explanation:

Hello.

In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:

7*411kJ/mol\\\\=2877kJ/mol

Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.

Best regards.

6 0
2 years ago
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