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tatuchka [14]
2 years ago
7

Which statement is true: Mg -> Mg2+ + 2e-

Chemistry
1 answer:
Damm [24]2 years ago
3 0

Answer:

(2) Mg²⁺ loses 2 electrons.

Explanation:

Let's consider the following half-reaction.

Mg ⇒ Mg²⁺ + 2 e⁻

Magnesium is a metal that loses 2 electrons to fulfill the octet rule. When magnesium loses electrons, the oxidation number increases from 0 to +2. This kind of half-reaction is known as oxidation, and has to be accompanied by a reduction of another species.

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How will increasing the pressure on the system affect this equilibrium reaction? 2H2(g)+O2(g) -> 2H2O(g)
fomenos
If u increase it, it could/would become unstable or Change into something different
7 0
2 years ago
Given the following reactions Fe2O3 (s) + 3CO (s) → 2Fe (s) + 3CO2 (g) ΔH = -28.0 kJ 3Fe (s) + 4CO2(s) → 4CO (g) + Fe3O4(s) ΔH =
Taya2010 [7]

Answer: The enthalpy of the reaction is -109 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Fe_2O_3(s)+3CO(s)\rightarrow 2Fe(s)+3CO_2(g)   \Delta H=-28.0kJ  \times 3    

3Fe_2O_3(s)+9CO(s)\rightarrow 6Fe(s)+9CO_2(g)   \Delta H=-84.0kJ     (1)

3Fe(s)+4CO_2(s)\rightarrow 4CO(g)+Fe_3O_4(s) \Delta H=+12.5kJ  \times 2  

6Fe(s)+8CO_2(s)\rightarrow 8CO(g)+2Fe_3O_4(s) \Delta H=+25.0kJ     (2)

The final reaction is:

Subtracting (2) from (1):

3Fe_2O_3(s)+CO(g)\rightarrow CO_2(g)+2Fe_3O_4(s) \Delta H=-84.0-(+25.0)=-109kJ

Thus the enthalpy of the reaction is -109 kJ

7 0
2 years ago
Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th
klasskru [66]

Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

7 0
2 years ago
Using only the following elements P, Br, and Mg, give the formulas for:A. an ionic compound. B. a molecular compound with polar
Talja [164]

Answer:

<h2>1. Ionic compound- MgBr_2</h2><h2>2. Polar molecular compound- PBr_3</h2>

Explanation:

Mg is a metal that has 12 atomic numbers and thus its electronic configuration is 1s^22s^22p^63s^2. The outer most shell of this element has 2 electrons so it loses 2 electrons and thus form Mg^2^+ ions. Br is a nonmetal and has 35 atomic number so its electronic configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5. Since its outermost shell has 7 electrons so it can accept one electron and thus forms Br^-. So magnesium ion and bromide ion combine and forms an ionic compound MgBr_2.

P is also a nonmetal and combine with Br with covalent bond and due to electronegativity differences form polar covalent compound such as PBr_3.

8 0
2 years ago
When filling a burette for a titration, adjust the burette so that______, preferably over a sink. Then,_______to add the titrant
artcher [175]

Answer:

Explanation:

When filling a burette for a titrant, adjust the burette so that the opening is near or below the eye leve preferably over the sink.

Then, use a funnel to add the titrant into the burette.

The titrant should be filled almost to the zero mark.

6 0
2 years ago
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