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jarptica [38.1K]
1 year ago
6

The shape of hair is determined in part by the pattern of disulfide bonds in keratin, its major protein. From first to last, arr

ange the five steps needed to induce permanent curls in hair. First step Last step Last step Answer Bank Keratin's a-helices convert to B-sheets. Keratin's disulfide bonds break. Physically curl the hair. Apply an oxidizing agent. Keratin's disulfide bonds reform to hold shape. Apply a thiol-containing reagent and gentle heat. Keratin's amino acids rearrange into the curled conformation.
Chemistry
1 answer:
UNO [17]1 year ago
4 0

Answer:

I.A thiol containing reagent and Heating(gentle)

II. Disulfide bond Breaker for Keratin

III. curling the hair physically

IV.A good oxidizing agent application

V. Disulfide bonds reformer for keratin  to hold the shape

Explanation:

The hair is mostly made of Keratin which is a structural proteins with about 15% cysteine

In order to change the hair appearance on the outside a reducing agent is required containing a thiol as to reduce the formation of the sulfide and disulfide bridges formation in the hair so the that any changes can be applied without the body naturally turning it back, i-e allowing easier manipulation after this  hairs are to be curled physically in order to keep this a oxidizing agent is applied and then finally a keratin reformer is added to hold the shape

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Part 1: Name the type of chemical reaction that occurs when magnesium chloride solution (MgCl2) reacts with sodium carbonate sol
garri49 [273]

Answer:

Mg would blow off. AI would be affective to copper but not to MG

Explanation:

7 0
1 year ago
5. A Dumas bulb is filled with chlorine gas at the ambient pressure and is found to contain 7.1 g of chlorine when the temperatu
kati45 [8]

Answer:

a. The original temperature of the gas is 2743K.

b. 20atm.

Explanation:

a. As a result of the gas laws, you can know that the temperature is inversely proportional to moles of a gas when pressure and volume remains constant. The equation could be:

T₁n₁ = T₂n₂

<em>Where T is absolute temperature and n amount of gas at 1, initial state and 2, final states.</em>

<em />

<em>Replacing with values of the problem:</em>

T₁n₁ = T₂n₂

X*7.1g = (X+300)*6.4g

7.1X = 6.4X + 1920

0.7X = 1920

X = 2743K

<h3>The original temperature of the gas is 2743K</h3><h3 />

b. Using general gas law:

PV = nRT

<em>Where P is pressure (Our unknown)</em>

<em>V is volume = 2.24L</em>

<em>n are moles of gas (7.1g / 35.45g/mol = 0.20 moles)</em>

R is gas constant = 0.082atmL/molK

And T is absolute temperature (2743K)

P*2.24L = 0.20mol*0.082atmL/molK*2743K

<h3>P = 20atm</h3>

<em />

7 0
1 year ago
Green light has a frequency of 6.01*10^14 Hz. What is the wavelength?
NemiM [27]
<span>λν = c

c= speed of light= 3.0x10^8 m/s
</span>λ=wavelength
v= frequency

Plug and Chug. 
8 0
1 year ago
What volume, in ml, of a 0.2089 m ki solution contains enough ki to react exactly with the cu(no3)2 in 43.88 ml of a 0.3842 m so
Triss [41]

The reaction is given as: 2Cu(NO_{3})_{2}+4KI\rightarrow 2CuI+I_{2}+4KNO_{3} Here, two moles of copper nitrate reacts with four moles of potassium iodide to give two moles of copper iodide, one mole of iodine and four moles of potassium nitrate. First, calculate the number of moles of copper nitrate. Number of moles is equal to the product of molarity and volume of solution in litre. Number of moles = 0.3842 M\times 0.04388 L    (1 L =1000 mL)

= 0.016858696 mole

Copper nitrate requires = 0.016858696 \times \frac{4}{2} mole of potassium iodide

= 0.033717392 mole of potassium iodide

Volume of solution in litre = \frac{number of moles}{Molarity}

Thus, volume of potassium iodide is  =\frac{0.033717392}{0.2089}

= 0.1614 L

1 L =1000 mL

Volume of potassium iodide in mL =161.4 mL

Hence, 161.4 mL 0.2089 M potassium iodide consist of sufficient potassium iodide to react with copper nitrate in 3.88 mL of a 0.3842 M solution of copper nitrate .





7 0
1 year ago
Determine the mass of oxygen in a 7.20 g sample of Al2(SO4)3.
Mekhanik [1.2K]

Given:

7.20 g sample of Al2(SO4)3

Required:

Mass of oxygen

Solution:

                Since you are not given a chemical reaction, just base your solution to the chemical formula given.

Molar mass of Al2(SO4)3 = 342.15 g/mol

7.20 g Al2(SO4)3 (1 mol/342.15g)(3mol O/2 mol Al)(1 mol O2/1/2 mol O2)(32g O2/1mol O2) = 4.04 g O2

5 0
1 year ago
Read 2 more answers
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