Question

Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the states of matter for each compound.

Answer 1

Answer:

$Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-$

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

$Hg(l)+O_2\rightarrow HgO$

Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

$Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-$

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

Best regards.