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uysha [10]
2 years ago
8

Two glasses labeled A and B contain equal amounts of water at different temperatures. Kim put an antacid tablet into each of the

two glasses. The table shows the time taken by the tablet to dissolve completely in the two glasses.
Antacid Experiment
Glass --> Time
A --> 40 seconds
B --> 10 seconds

Which of the following statements is correct?

A. The water in Glass A is warmer than the water in Glass B; therefore, the water particles in Glass A are stationary.

B. The water in Glass A is cooler than the water in Glass B; therefore, the water particles in Glass A are stationary.

C. The water in Glass A is warmer than the water in Glass B; therefore, the particles in Glass A move faster.

D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.
Chemistry
2 answers:
skelet666 [1.2K]2 years ago
6 0

Answer:

Option D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Explanation:

Solubilities of solutes are enhanced when the temperature is increased.

From the experiment conducted,

It is evident that glass B temperature is higher than glass A temperature, because the solute dissolves faster in glass B than in glass A . This implies that glass A is cooler than glass B, hence the particles in A will move slower than that in B.

valentina_108 [34]2 years ago
5 0

Answer:

D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower

Explanation:

In science, temperature is defined as a measure of the average kinetic energy of the molecules of a substance. The more the velocity of the molecules of a substance, the greater their kinetic energy and the greater their temperature.

When molecules of solvent move faster, they collide more frequently with solute particles hence dissolution occurs faster at a higher temperature and molecular slowed compared to another system at lower temperature and lower molecular speed.

The higher temperature of particles in B will see to the faster dissolution of the antacid in B compared to A

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Which of the following NOT a principle of deep ecology, according to Arne Naess? All life has intrinsic value Environment must b
motikmotik

Answer:

On the picture are all principles cited on wikipedia.

Explanation:

So the answer is

1. Environment must be exploited to improve living standards

2. Flourishing human and nonhuman life depends on diversity of life forms

5 0
2 years ago
A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to the stoi- chiometric point.
Dmitrij [34]

Answer:

Molar concentration of the weak acid solution is 0.0932

Explanation:

Using the formula: \frac{C_aV_a}{C_bV+b}  = \frac{n_a}{n_b}

Where Ca = molarity of acid

Cb = molarity of base = 0.0981 M

Va = volume of acid = 25.0 mL

Vb = volume of base = 23.74 mL

na = mole of acid

nb = mole of base

Since the acid is monopromatic, 1 mole of the acid will require 1 mole of NaOH. Hence, na = nb = 1

Therefore, C_a = \frac{C_bV_b}{V_a}

Ca = 0.0981 x 23.74/25.0

                 = 0.093155 M

To 4 significant figure = 0.0932 M

3 0
2 years ago
Read 2 more answers
Match each situation below to a letter on the illustration.
Mnenie [13.5K]

Answer:a

Explanation:

4 0
2 years ago
Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

5 0
2 years ago
Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpentina. It was first synthesized in 1956 by No
liraira [26]

Answer:

  • Molality = 0.066 m
  • Molar mass = 608.36 g/mol

Explanation:

It seems the question is incomplete. However a web search us shows this data:

" Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpentina. It was first synthesized in 1956 by Nobel Prize winner R. B. Woodward. It is used as a tranquilizer and sedative. When 1.00 g reserpine is dissolved in 25.0 g camphor, the freezing-point depression is 2.63 °C (Kf for camphor is 40 °C·kg/mol). Calculate the molality of the solution and the molar mass of reserpine. "

The <em>freezing-point depression</em> is expressed by:

  • ΔT=Kf * m

We put the data given by the problem and <u>solve for m</u>:

  • 2.63 °C = 40°C·kg/mol * m
  • m = 0.06575 m

For the calculation of the molar mass:<em> Molality</em> is defined as moles of solute per kilogram of solvent:

  • 0.06575 m = Moles reserpine / kg camphor
  • 25.0 g camphor ⇒ 25.0/1000 = 0.025 kg camphor

We<u> calculate moles of reserpine:</u>

  • 0.06575 m = Moles reserpine / 0.025 kg camphor
  • Moles reserpine = 1.64x10⁻³ mol

Finally we use the mass of reserpine and the moles to calculate <u>the molar mass</u>:

  • 1.00 g reserpine / 1.64x10⁻³ mol = 608.36 g/mol

<em>Keep in mind that if the data in your problem is different, the results will be different. But the solving method remains the same.</em>

8 0
2 years ago
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