Which element has the greatest density at stp? calcium, chlorine, carbon or copper?
2 answers:
The element that has maximum density at STP is copper.
Further explanation:
The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:
1. Intensive properties:
These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.
2. Extensive properties:
These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, energy, size, weight, and length are some of the examples of extensive properties.
Density is a characteristic property of the substance. It is defined as the mass per unit volume. It is generally represented by .
The formula to calculate the density of the liquid is,
Standard Temperature and Pressure is denoted as STP and the volume of 1 mole of gas at STP is 22.4 litres.
The volume is constant and therefore density is directly related to mass.
Among the given elements copper has the highest molar mass and that is . Therefore the element that has maximum density at STP is copper.
Learn more:
1. Calculation of density: <u>brainly.com/question/778841 </u>
2. Determine how many moles of water produce: <u>brainly.com/question/1405182 </u>
Answer details:
Grade: Middle School
Subject: Chemistry
Chapter: Density
Keywords: density, mass, volume, STP, intensive, extensive, characteristic property, element, copper, chlorine, calcium, and carbon.
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Answer:
i. n = 5
ii. ΔE = 7.61 × KJ/mole
Explanation:
1. ΔE = (1/λ) = -2.178 × (
-
)
(1/434 × ) = -2.178 ×
(
)
⇒ 434 × = (1/-2.178 ×
)
But, = 2
434 × = (1/2.178 ×
)
434 × × 2.178 ×
=
⇒ = 5
Therefore, the initial energy level where transition occurred is from 5.
2. ΔE = hf
= (hc) ÷ λ
= (6.626 × 10−34 × 3.0 × ) ÷ (434 ×
)
= (1.9878 × ) ÷ (434 ×
)
= 4.58 × J
= 4.58 × KJ
But 1 mole = 6.02×, then;
energy in KJ/mole = (4.58 × KJ) ÷ (6.02×
)
= 7.61 × KJ/mole