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uysha [10]
1 year ago
11

Before running a titration, you calculate the expected endpoint. However, when performing the experiment, you pass the expected

endpoint with no visible color change. What is the most likely problem with the titration set-up
Chemistry
1 answer:
Leviafan [203]1 year ago
8 0

The question is incomplete; the complete question is;

Before running a titration, you calculate the expected endpoint. However, when performing the experiment, you pass the expected endpoint with no visible color change. What is the most likely problem with the titration set- up? Select one

a) There was an air bubble in the burette tip.

b) There is not enough indicator in the analyte.

c) The burette tip is leaking titrant into the analyte.

d) The analyte solution is being stirred too quickly

Answer:

a) There was an air bubble in the burette tip.

Explanation:

Titration involves the determination of the concentration of a solution by measuring the volumes of reactants used in the reaction. The concentration of one of the species must be known while the concentration of the other specie is to be determined by the volumetric analysis.

However, if there are air bubbles at the tip of the burette, this will cause less volume of titrant to be delivered from the burette than expected. Hence, the analyst may think that a certain volume of titrant has been delivered while in reality, a lesser volume was actually delivered due to the air bubbles present. Hence, the analyst may pass the expected endpoint without any colour change because of this problem.

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If these are you choices: 
(1)  Both the solid and the liquid are good conductors.

(2)  Both the solid and the liquid are poor conductors.

(3)  The solid is a good conductor, and the liquid is a poor conductor.

(4)  The solid is a poor conductor, and the liquid is a good conductor. 

 Then the answer is number 4. This is because ionic compound conducts electricity when it is dissolved in water.

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2 years ago
HELP! Ethanol has a density of 0.8 g/cm3. a. What is the mass of 225 cm3 of ethanol? b. What is the volume of 75.0 g of ethanol?
IRINA_888 [86]

Answer:

The correct answers are:

a) 180 g

b) 93.7 cm³

Explanation:

The density of a substance is the mass of the substance per unit of volume. So, it is calculated as follows:

density= mass/volume

From the data provided in the problem:

density = 0.8 g/cm³

a) Given: volume= 225 cm³

mass= density x volume = 0.8 g/cm³ x 225 cm³ = 180 g

b) Given: mass= 75.0 g

volume = mass/density = 75.0 g/(0.8 g/cm³)= 93.75 cm³≅ 93.7 cm³

5 0
1 year ago
To win in a qualifying round in a duck race, a duck's rate of change needs to be 35.4 meters/second. Kate was training her duck
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Answer:

i believe that 14  at a higher rate is the answer

Explanation:

3 0
1 year ago
Identify the MOs that react to form cyclohexene. HOMO of 1,3-butadiene and LUMO of ethylene LUMO of 1,3-butadiene and LUMO of et
BARSIC [14]

Answer:

HOMO of 1,3-butadiene and LUMO of ethylene

HOMO of ethylene LUMO of 1,3-butadiene

Explanation:

1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.

According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.

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1 year ago
Radioactive elements decay at a know rate known as half-life. Choose all of the correct statements concerning half-life. Carbon-
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Explanation:

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Options;

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- Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. This is correct. 3 * 76000 = 228,000

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- Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. This is incorrect. Mass after 4 half lives (6 / 1.5) = 2.5 gram (40 / 2 / 2 /2 / 2)

- Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years. This is incorrect. Original sampe = 240 gram. So after 2 half lives (105,000/52500), mass left = 60 (240 / 2 /2)

6 0
1 year ago
Read 2 more answers
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