Question

Using only the following elements P, Br, and Mg, give the formulas for:A. an ionic compound. B. a molecular compound with polar covalent bonds that obeys the octet rule and has no formal charges.

Answer 1

Answer:

1. Ionic compound- $MgBr_2$

2. Polar molecular compound- $PBr_3$

Explanation:

Mg is a metal that has 12 atomic numbers and thus its electronic configuration is $1s^22s^22p^63s^2$. The outer most shell of this element has 2 electrons so it loses 2 electrons and thus form $Mg^2^+$ ions. Br is a nonmetal and has 35 atomic number so its electronic configuration is $1s^22s^22p^63s^23p^64s^23d^1^04p^5$. Since its outermost shell has 7 electrons so it can accept one electron and thus forms $Br^-$. So magnesium ion and bromide ion combine and forms an ionic compound $MgBr_2$.

P is also a nonmetal and combine with Br with covalent bond and due to electronegativity differences form polar covalent compound such as $PBr_3$.