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Dmitrij [34]
2 years ago
8

How many grams of AlF3 are in 2.64 moles of AlF3?

Chemistry
1 answer:
Svetach [21]2 years ago
3 0
The number of grams  of AlF3 that are  in 2.64 moles  of AlF3    is  calculated as  below

mass = moles  x molar mass

= 2.64  moles x 84 g/mol  =221. 76   grams  of AlF3
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Draw the best lewis structure for bro4- and determine the formal charge on bromine
Svetach [21]

Answer :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The electrons are represented by dot.

The given molecule is, perbromate ion.

Bromine has '7' valence electrons and oxygen has '6' valence electron.

Therefore, the total number of valence electrons in perbromate ion, BrO_4^- = 7 + 4(6) + 1 = 32

According to Lewis-dot structure, there are 14 number of bonding electrons and 18 number of non-bonding electrons.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on }Br=7-0-\frac{14}{2}=0

The Lewis-dot structure of perbromate ion is shown below.

7 0
2 years ago
Read 2 more answers
The density of a 50% solution of naoh is 1.525 g/ml. what volume of a solution that is 50% by weight naoh is required to make 0.
jolli1 [7]
We consider that the 50% given in this item is by volume. Molarity is the unit of concentration that takes into account the number of moles of the solute and the number of moles of the substance.

      number of moles of NaOH = (0.1 moles / L)(0.4 L)
                      n = 0.04 moles of NaOH

If we are to take the basis of 1 mL of 50% NaOH solution, 
  
                  (1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
The number of moles is,
                  0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH

                volume of solution required = (0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
                 
                 volume of solution required = 2.09 mL

Answer: 2.09 mL
3 0
2 years ago
Assume the following substances are soluble in water.
solmaris [256]

Ammonium carbonate will form 3 moles of ions.

Methyl alcohol will form 0 moles of ions.

Methane will form 0 moles of ions.

Aluminum sulfite will form 3 moles of ions.

Hydrobromic acid will form 2 moles of ions.

Explanation:

One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.

(NH₄)₂CO₃ (s) + H₂O (l) → 2 NH₄⁺ (aq) + CO₃²⁻ (aq) + H₂O (l)

One mole of methyl alcohol will form 0 moles of ions when dissolved in water.

(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)

One mole of methane will form 0 moles of ions when dissolved in water.

Methane does not react with water (in normal conditions) so will not form ions.

One mole of aluminum sulfite will form 3 moles of ions when dissolved in water.

Al₂SO₃ (s) + H₂O (l) → 2 Al₃⁺ (aq) + SO₃²⁻ (aq) + H₂O (l)

One mole of hydrobromic acid will form 2 moles of ions when dissolved in water.

HBr (l) +  H₂O (l) → Br⁻ (aq) + H₃O⁺ (aq)

Learn more about:

solvation of ions

brainly.com/question/5384053

#learnwithBrainly

8 0
2 years ago
What mass of ethane (CH3CH3) is contained in 50.0 mL of a 13.9% by mass solution of ethane in hexane?
evablogger [386]

Answer:

Mass of ethane which is contained in 50 mL is 4.25 g

Explanation:

13.9% by mass, means that in 100 g of solution, we have 13.9 grams of solute.

Density of solution is 0.611 g/mL

Volume of solution is 50 mL

Density = mass of solution / 50mL

0.611 g/mL . 50 mL = mass of solution → 30.55 g

Now, the rule of three.

In 100 grams of solution we have 13.9 grams of solute

30.5 grams of solution we have (30.55 . 13.9) / 100 = 4.25 g  

5 0
2 years ago
During your future endeavors in chemistry you will inevitably do a bunch of acid-base problems. Of the strong bases above, calci
Alex777 [14]

Answer:

d. There are two moles of hydroxide for each mole of these compounds.

Explanation:

calcium hydroxide, strontium hydroxide, and barium hydroxide all have two hydroxide compunds. the difference between each of these compounds is they all contain a different element along with hydroxide.

6 0
2 years ago
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