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Dmitrij [34]
2 years ago
8

How many grams of AlF3 are in 2.64 moles of AlF3?

Chemistry
1 answer:
Svetach [21]2 years ago
3 0
The number of grams  of AlF3 that are  in 2.64 moles  of AlF3    is  calculated as  below

mass = moles  x molar mass

= 2.64  moles x 84 g/mol  =221. 76   grams  of AlF3
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OH⁻ from strong base (NaOH) react with weak acid from buffer (HOCl) according to the following equation:
         OH⁻ + HOCl → H₂O + OCl⁻
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2 years ago
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Which of the following statements is true about the following reaction?
MAVERICK [17]

The correct reaction equation is:

3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>

a) <u>22.4 L of CO_{2} gas</u> is produced only when <u>\frac{22.4}{3} L of  C_{6}H_{8}O_{7}</u> is reacted with 22.4 L of NaHCO_{3}. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

8 0
2 years ago
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How many molecules are there in 345 grams of carbon dioxide?
Mekhanik [1.2K]
You take the grams of CO₂ times Avogadro's number divided by the molar mass.
6 0
1 year ago
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If 36.9 mL of B2H6 reacted with excess oxygen gas, determine the actual yield of B2O3 if the percent yield of B2O3 was 75.7%. (T
zhuklara [117]

Answer: The actual yield of B_2O_3 is 60.0 g

Explanation:-

The balanced chemical reaction :

B_2H_6(l)+3O_2(g)\rightarrow B_2O_3(s)+3H_2O(l)

Mass of B_2H_6 =Density\times Volume=1.131g/ml\times 36.9ml=41.7g

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} B_2H_6=\frac{41.7g}{27.668g/mol}=1.51moles

According to stoichiometry:

1 mole of B_2H_6 gives = 1 mole of B_2O_3

1.51 moles of B_2H_6 gives =\frac{1}{1}\times 1.51=1.51 moles of B_2O_3

Theoretical yield of B_2O_3=moles\times {Molar mass}}=1.14mol\times 69.62g/mol=79.3g

Percent yield of B_2O_3= 75.7\%

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

75.7\%=\frac{\text{Actual yield}}{79.3}\times 100

{\text{Actual yield}}=60.0g

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7 0
2 years ago
Two students are working together to build two models. Both models will represent the molecular structure of sodium bicarbonate,
vfiekz [6]

Answer:

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>

Explanation:

Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.

Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

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