Answer:

Explanation:
Hello,
In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

That in terms of the heat capacities, masses and temperature changes turns out:

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Best regards.
Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1
= 1000L
Multiply by 1000 to convert to L/s
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt (X) is contained in 2,592,000,000L/day
X= 
X= 129,600,000,000 mg/day
convert this value to kg/day by multiply by 
X= 129,600kg/day
<u>Answer:</u> The equilibrium constant for
equation is 
<u>Explanation:</u>
The given chemical equation follows:

The value of equilibrium constant for the above equation is 
Calculating the equilibrium constant for the given equation:

The value of equilibrium constant for the above equation will be:

Hence, the equilibrium constant for
equation is 
<span>Molar mass(C)= 12.0 g/mol
Molar mass (O2)=2*16.0=32.0 g/mol
Molar mass (CO2)=44.0 g/mol
18g C*1mol C/12 g C = 1.5 mol C
C + O2 → CO2
from reaction 1 mol 1 mol 1 mol
from problem 1.5 mol 1.5 mol 1.5 mol
1.5 mol O2*32 g O2/1 mol O2 = 48 g O2
In reality this reaction requires only 48 g O2 for 18 g carbon.
And from 18 g carbon you can get only
1.5 mol CO2*44 g CO2/1 mol CO2=66 g CO2
But these problem has 72g CO2. The best that we can think, it is a mix of CO2 and O2.
So to find all amount of O2 that was added for the reaction (probably people who wrote this problem wanted this)
we need (the mix of 72g - mass of carbon 18 g)= 54 g.
So the only answer that is possible is </span><span>2.) 54 g.</span>
Hey there !
Molar mass carbon dioxide:
CO2 = 44.01 g/mol
1) number of moles :
1 mole CO2 ------------- 44.01 g
(moles CO2) ------------ 243.6 g
moles CO2 = 243.6 * 1 / 44.01
moles CO2 = 243.6 / 44.01
=> 5.535 moles of CO2
Therefore:
1 mole -------------------- 6.02x10²³ molecules
5.535 moles ------------ ( molecules CO2)
molecules CO2 = 5.535 * ( 6.02x10²³) / 1
=> 3.33x10²⁴ molecules of CO2