Answer:
Explanation:
A <em>combustion reaction</em> is the reaction with oxygen along with the release of energy in form of heat or light.
Organic compounds (like CH₄) undergo combustion forming water and CO₂.
The combustion reaction of CH₄ is:
Hence, the first equation from the choices is not showing the combustion reaction of CH₄.
Not only organic compounds can undergo combustion. Metals and no metals can undergo combustion, i.e. metals and no metals can react with oxygen releasing light or heat.
The reaction of copper and oxygen (second choice) is a combustion reaction:
The formation of water (2H₂ + O₂ → 2H₂O) is other example of a combustion reaction where no organic compounds are involved.
On the other hand, the other two equations from the choice list are not reactions with oxygen, so they do not show combustion reactions.
Explanation:
As the given reaction is as follows.
So, according to the balanced equation, it can be seen that rate of formation of 
will be twice the rate of disappearance of 
.
And, it is known that rate of disappearance of reactant will be negative and rate of formation of products will be positive value.
This means that,
Rate of the reaction = -Rate of disappearance of
= ![k[H_{2}S][Cl_{2}]](https://tex.z-dn.net/?f=k%5BH_%7B2%7DS%5D%5BCl_%7B2%7D%5D)
= 
= 
M/s
Therefore, calculate the rate of formation of as follows.
Rate of formation of = 
= 
M/s
Thus, we can conclude that the rate of formation of is M/s.
It's a because if you add them together you till get 1.40
Answer:
The specific heat capacity of liquid and the het of vaporization is used.
.
Explanation:
Step 1: Data given
A substance at temperature 2°C.
The substance has a melting point of −10°C and a boiling point of 155°C.
The initial temperature is 2°C which is between the melting point (-10°C) and the boiling point (155°C). At 2°C, the substance is liquid.
At 155°C, the substance changes from liquid to gas.
To calculate the heat gained for the change of 2°C liquid to 155°C liquid, specific heat capacity of the liquid (C) is needed.
To calculate the heat gained for the change of liquid to 155°C gas, heat of vaporization (D) is needed.
The <u>specific heat of the solid is not used</u> because the substance is changed from liquid to gas. it doesn't come in the state of solid.
<u>Heat of fusion is not used</u>, because it's used when there is a change from its state from a solid to a liquid,
<u>The specific heat capacity of the gas is not used</u>, because the substance only formes gas after reaching 155 °C
Answer:
EMF = -0.17 V
No
Explanation:
For the reaction :
Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s)
we will be using the Nersnt equation to calculate Ecell:
Ecell = Eº -0.0592 V/2 ln Q
where Q = ( Fe⁺² )/ (Cd²⁺)
and (Fe²⁺) and (Cd²) are the molar concentration of Fe²⁺ and Cd²⁺
Reduction
Fe²⁺ + 2e⁻ ⇒ Fe(s) Eº red = -0.4400 V
Oxidation
Cd (s) ⇒ Cd²⁺ + 2e⁻ Eº ox = +0.4000 V
Eºcell = Eox + Ered = 0.4000 V + (-0.4400 V) = -0. 0400 V
Ecell = Eº -0.0692 V/2 ln Q = -0.0400 V - 0.0592/2 ln ( 0.80/0.010 ) = -0.17V
No because Eºcell is negative and ΔºG will be positive since
ΔºG = -nFEºcell
