We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced
The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O
First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.
Na2CO3 = 2Na+ + CO3^2-
7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
Answer:
There are
17.01
Explanation:
The chemical formula for calcium phosphate is
Ca
3
(PO
4
)
2
. This means that in one mole of calcium phosphate, there are three calcium ions and two phosphate ions.
<u>Answer:</u> The wavelength of light is 
<u>Explanation:</u>
To calculate the wavelength of light, we use Rydberg's Equation:

Where,
= Wavelength of radiation
= Rydberg's Constant = 
= Final energy level = 3
= Initial energy level = 6
Putting the values in above equation, we get:

Hence, the wavelength of light is 