<h2>Selective & Differential Medium</h2>
Explanation:
- Selective media allow specific types of organisms to develop, and inhibit the development of different living beings. The selectivity is cultivated in a few ways.For model, living beings that can use a given sugar are handily screened by making that sugar the main carbon source in the medium. On the other hand,selective hindrance of certain sorts of microorganisms can be accomplished by adding dyes, anti-infection agents, salts or explicit inhibitors which influence the digestion or enzyme systems of the living beings
- Differential media are utilized to separate firmly related life forms or groups of living beings. owing to the pre of specific colors or synthetic compounds in the media, the creatures will deliver trademark changes or development designs that are utilized for ID or separation. An assortment of particular and differential media are utilized in clinical, demonstrative and water contamination research facilities, and in food and dairy laboratories
- Selective media because elevated NaCI level is designed to help grow selective bacteria.differential media because the fermented sugar gives off a yellow halo which allows for differentiate between bacteria
Answer:
The equations are
1) 
2) 
Explanation:
There are two ionization steps in the dissociation of hydroselenic acid.
In first dissociation the H₂Se loses one proton and forms hydrogen selenide ion as shown below:
The next step is again removal of a proton from the base formed above.
The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.
Both of these molecules contain double bonds, which has sp^2 hybridization and they possess a trigonal planar geometry. In trigonal planar geometry, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree.
Answer:- 38.2 g.
Solution:- The equation used for solving this type of calorimetry problems is:
where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.
Water temperature is increasing from 14.5 degree C to 50.0 degree C.
= 35.5 degree C
q is given as 5680 J and specific heat value is 
.
The equation could be rearranged for m as:
Let's plug in the values in it:
m = 38.2 g
So, the mass of water in the kettle is 38.2 g.
