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Stells [14]
2 years ago
15

Match each set of quantum numbers to the correct subshell description by typing in the correct number. 1: n = 2, l = 0 2p: 2: n

= 3, l = 2 3d: 3: n = 1, l = 0 2s: 4: n = 2, l = 1 4f: 5: n = 4, l = 3 1s: Type in the maximum number of electrons that can be present in each shell or subshell below. n = 5 shell: n = 2 shell: n = 2, l = 0 subshell: n = 2, l = 1 subshell: 3d subshell: 2s subshell: 5f subshell:
Chemistry
2 answers:
kvasek [131]2 years ago
7 0

Answer:

edge

Explanation:

Match each set of quantum numbers to the correct subshell description by typing in the correct number.

1: n = 2, l = 0 2p:  

4

2: n = 3, l = 2 3d:  

2

3: n = 1, l = 0 2s:  

1

4: n = 2, l = 1 4f:  

5

5: n = 4, l = 3 1s:  

3

Reil [10]2 years ago
4 0

Answer:

4

2

1

5

3

Explanation:

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The concentration of ozone in a sample of air that has a partial pressure of O3 of 0.33 torr and a total pressure of air of 695
Goryan [66]

Answer:

0.047 %

Explanation:

Step 1: Given data

  • Partial pressure of ozone (pO₃): 0.33 torr
  • Total pressure of air (P): 695 torr

Step 2: Calculate the %v/v of ozone in the air

Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.

<em>%v/v = pO₃/P × 100%</em>

%v/v = 0.33 torr/695 torr × 100%

%v/v = 0.047 %

8 0
2 years ago
For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided
SVETLANKA909090 [29]

Answer:

\frac{1}{24}

Explanation:

Given:

For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.

To find: fraction of the whole athletic field reserved for each fifth class

Solution:

Fraction of the whole athletic field reserved for four fifth classes = \frac{1}{6}

So, fraction of the whole athletic field reserved for each fifth class = \frac{1}{4}(\frac{1}{6})=\frac{1}{24}

3 0
2 years ago
Buffer consists of undissociated acid (ha) and the ion made by dissociating the acid (a-). How does this system buffer a solutio
docker41 [41]

In buffer solution there is an equilibrium between the acid  HA and its conjugate base A⁻: HA(aq) ⇌ H⁺(aq) + A⁻(aq).

When acid (H⁺ ions) is added to the buffer solution, the equilibrium is shifted to the left, because conjugate base (A⁻) reacts with hydrogen cations from added acid, according to Le Chatelier's principle: H⁺(aq) + A⁻(aq) ⇄ HA(aq). So, the conjugate base (A⁻) consumes some hydrogen cations and pH is not decreasing (less H⁺ ions, higher pH of solution).

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

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2 years ago
After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the R
Step2247 [10]

Answer: Thus 24.0 g of SO_2 would be needed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}      

\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles

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5 0
2 years ago
Baking soda is a critical component of chemical
Lostsunrise [7]
Baking soda is a critical component of chemical spill kits because baking soda has neutralizing agents. Baking soda is a sodium bicarbonate, a natural substance that maintains the ph balance. Baking soda neutralizes org acids and bases. It eliminates odors instead of covering them up.
8 0
2 years ago
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