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2 years ago

Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead

Chemistry

1 answer:

ankoles [38]2 years ago

4 0

Answer: Heating a crucible to remove water from a hydrate.

Explanation:

The options are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

d. Heating a crucible to remove water from a hydrate.

The procedure that can be performed on a hot plate are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

It should be noted that the hot plate cannot be used for heating of crucible in order to remove water from a hydrate. It is not advisable for someone to heat any silica or ceramic objects on a hot plate.

Therefore, heating a crucible to remove water from a hydrate is the correct option.

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Og is the noble gas after rn. to go from [rn] to [og], you must fill four subshells (s, p, d, and f) with a total of 32 electron

Juliette [100K]

Answer : 50 electrons are needed to fill all five subshells

Explanation :

To move from Rn to Og, we need to fill 4 subshells which are s, p d & f.

The maximum number of electrons that can be added to each orbital are given below.

s = 2 e⁻

p = 6 e⁻

d = 10 e⁻

f = 14 e⁻

If we add all these electrons, we get 2 + 6 + 10 + 14 = 32 electrons.

We need to add 32 electrons to the atomic number of Rn to get the atomic number of Og.

Hence we say that the atomic numbers of 6th and 7th period elements of the same group differ by 32.

To go from Og to the next noble gas, we have to theoretically fill 5 subshells.

The maximum electrons that can be added to g orbital are 18.

Therefore in order to go from Og to next element, we would add

2 + 6 + 10 + 14 + 18 = 50 electrons.

50 electrons are needed to fill all five subshells.

5 0

2 years ago

Read 2 more answers

You are given a compound with the formula mcl2, in which m is a metal. you are told that the metal ion has 26 electrons. what is

Nookie1986 [14]

Answer:

Nickle

Explanation:

In statement it is given that the metal "M" has a formula "MCl₂" which means it has a charge of +2 as each Chlorine atom has -1 charge. Therefore, it is cleared that this metal has lost 2 electrons and originally it was carrying 28 electrons.

After that periodic table is concerned and a metal with 28 atomic number was tracked because a neutral atom with 28 electrons must have 28 protons and protons are infact the atomic number.

Hence, in periodic table the metal with 28 atomic number is found to be Nickle.

6 0

2 years ago

Hydrogen bonds are approximately _____% of the bond strength of covalent c-c or c-h bonds.

Lelu [443]

Hydrogen bonds are approximately 5% of the bond strength of covalent C-C or C-H bonds.
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.

4 0

2 years ago

Tell whether the following pairs of compounds are identical, constitutional isomers, stereoisomers, or unrelated. (a) cis-1,3-Di

Aleks04 [339]

Answer:

(a) Constitutional Isomers

(b) Constitutional Isomers

Explanation:

Constitutional isomers are also known with the name Structural Isomers. These are the compounds which have same chemical formula but differ in arrangement of atoms i.e. structure.

Both the compounds cis-1,3-dibromocyclohexane and trans-1,4-dibromocyclohexane have the same chemical formula $C_{6} H_{10} Br_{2}$ but have different structure as shown in the image below.

In the second case the compounds 2,3-dimethylhexane and 2,3,3-trimethylpentane, both have same chemical formula $C_{8} H_{18}$ but have different structures which is shown in the image below.

Thus it is clear that in both the groups (a) and (b) the given compounds are Constitutional Isomers.

7 0

2 years ago

A gold wire has a diameter of 1.00 mm. What length of this wire contains exactly 1.00 mol of gold? (density of Au = 17.0 g/cm3)

allochka39001 [22]

Answer:

The answer to your question is 7160 cm

Explanation:

Data

diameter = 1 mm

length = ?

amount of gold = 1 mol

density = 17 g/cm³

Process

1.- Get the atomic mass of gold

Atomic mass = 197 g

then, 197g ------------ 1 mol

2.- Calculate the volume of this wire

density = mass/volume

volume = mass/density

volume = 197/17

volume = 5.7 cm³

3.- Calculate the length of the wire

Volume = πr²h

solve for h

h = volume /πr²

radius = 0.05 cm

substitution

h = 5.7/(3.14 x 0.05²)

h = 5.7 / 0.0025

h = 7159.2 cm ≈ 7160 cm

8 0

2 years ago

Read 2 more answers