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eduard
1 year ago
6

Which organisms are extremely small and use hosts as both home and food supply?

Chemistry
2 answers:
Tasya [4]1 year ago
8 0
<span><u><em>Answer:</em></u>
Parasites

<u><em>Explanation:</em></u>
Parasites are a type of <u>pathogen</u> that survive by hitchhiking a host. They usually do this as they perceive the host as type of protection for them in order to survive.

Beside this protection, the host provides these parasites with the necessary nutrition as they feed directly from the host.
<u>They can feed on different parts from the hosts including:</u>
1- the digestion as in case of tapeworm
2- brain tissue as in case of brain-eating ameoba
3- blood

Parasites' presence in the host's body can alter the functionalities and processes within the body and cause sickness.

Hope this helps :)</span>
Simora [160]1 year ago
7 0
I would say that the bacteria who live inside one's gut would constitute very small organisms that are extremely small and inhabit the gut as home and also feed off it to survive and in this case probably have a symbiotic relationship with our bodies as they help us to break down and digest food.
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Based on the tiles shown, how many moles of oxygen gas (o2) are needed to produce 36.04 grams of water (h2o) when reacting with
madreJ [45]
We calculate for the number of moles of water given its mass by dividing the given mass by the molar mass. 
                               n water = (36.04 g) / (18 g/mol) 
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From the given balanced equation, every 6 moles of water produced will require 7 moles of oxygen.
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3 0
2 years ago
Jill is doing an experiment on the movement of pill bugs. She will place the pill bugs on flat surfaces covered with diffirent m
Ostrovityanka [42]

Answer:D

Explanation:

6 0
2 years ago
Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6
Volgvan

Answer:

2.0x10^{-5}\frac{mol}{L}

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

CuCl(s)\rightarrow Cu^++Cl^-

And its equilibrium expression is:

Ksp=[Cu^+][Cl^-]

We can represent the molar solubility via the reaction extent as x, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

1.0x10^{-6}=(x)(0.050+x)

Thus, solving for x, we obtain:

1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0

By using the quadratic equation, we obtain:

x_1=2.0x10^{-5}M\\\\x_2=-0.05M

Clearly, the solution is x_1=2.0x10^{-5}M because no negative results are

allowed. Therefore, the molar solubility is:

2.0x10^{-5}\frac{mol}{L}

Best regards!

5 0
1 year ago
In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0
2 years ago
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