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Katena32 [7]
2 years ago
6

When the volume of a gas is changed from mL to 852 mL the temperature will change from 315c to 452c

Chemistry
1 answer:
zhenek [66]2 years ago
4 0

Answer:

The starting volume is 691 mL

Explanation:

The compete question is:

When the volume of a gas is changed from ___ mL to 852 mL, the temperature will change from 315 °C to 452 °C. What is the starting volume?

Write Charles Law and substitute values in:

   V1 / T1 = V2 / T2

    V1 / 588 K = 852 mL / 725 K

   V1 (725 K) = (852 mL) (588 K)

   V1 = 691 mL

Note the large °C values, trying to get you to forget to add 273. Remember, only Kelvin temperatures are allowed in the calculations.

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Travka [436]
N_2 (g) + 3H_2 (g) rightarrow 2NH_3 (g) volume of H_2 = 32.44 At STP 1 mole of H_2 = 22.4L ? mole of H_2 = 32.4L therefore moles of H_2
8 0
2 years ago
Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
In nature, boron is monoatomic. Therefore, its formula is B.
On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

Now, we need to balance this equation. As you can see, we have two fluorine moles entering the reaction and 3 formed in the products.
Balancing the equation, we will reach the following balanced reaction:
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7 0
2 years ago
The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s
denis-greek [22]

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

8 0
2 years ago
Nuclear power plants produce energy using fission. One common fuel, uranium-235, produces energy through the fission reaction 23
Vikentia [17]

Answer:

mass of U-235  = 15.9 g (3 sig. figures)

Explanation:

1 atom can produce -------------------------> 3.20 x 10^-11 J energy

x atoms can produce ----------------------> 1.30 x 10^12 J energy

x = 1.30 x 10^12 / 3.20 x 10^-11

x = 4.06 x 10^22 atoms

1 mol ----------------------> 6.023 x 10^23 atoms

y mol ----------------------> 4.06 x 10^22 atoms

y = 0.0675 moles

mass of U-235 = 0.0675 x 235 = 15.8625

mass of U-235  = 15.9 g (3 sig. figures)

7 0
2 years ago
Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list
FromTheMoon [43]

Options:

monoglycerides

cocamide DEA

folic acid

iron chromium ion

peroxide

lauryl glucoside

disodium phosphate

Answer and Explanation:

The added chemicals are:

  • monoglycerides
  • folic acid
  • iron
  • disodium phophates

Monoglycerides are fats added for flavour. Folic cid and iron are vitamins added for nutritional value. disodium phosphate is a food additive for enhancing flavour.

The remaining ingredients are organic based.

3 0
2 years ago
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