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scZoUnD [109]
1 year ago
9

Water is sometimes removed from the products of a reaction by placing the products in a closed container with excess P4O10. Wate

r is absorbed by the following reaction. P4O10 + 6H2O es001-1.jpg 4H3PO4 What is the mole ratio of water to H3PO4? Do not simplify the ratio. Hes001-2.jpgO:Hes001-3.jpgPOes001-4.jpg = :4
Chemistry
2 answers:
Ganezh [65]1 year ago
8 0

Answer : The correct answer for mole ratio of H₂O : H₃PO₄ = 6: 4 .

Mole ratio :

It is defined as mole of one substance to another substance in a balanced reaction . In the balanced reaction , the coefficient written before the substances are taken as moles of that substance.

The given balanced reaction between P₄H₁₀ and H₂O is :

P₄O₁₀ + 6 H₂O → 4 H₃PO₄

Mole of H₂O = 6

Mole of H₃PO₄ = 4

Hence mole ratio of Water : H₃PO₄ = 6 : 4


Anna11 [10]1 year ago
3 0
H2O:H3PO4<span> = 6:4.
I just took the test and got it right!

</span>
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A scientist has isolated a chemical compound that is partially soluble in water. The chemical helps keep water-soluble substance
VLD [36.1K]

Answer:

Based on the information, the compound is a phospholipid.

Explanation:

Phospholipids are made up of a fatty acid tail which is hydrophobic in nature and a head which comprises of phosphates that is hydrophilic in nature. Hence, phospholipids are amphiphilic compounds so they will be partially soluble in water and will allow water-soluble substances to mix with fats.

Hence, the composition of the substance described in the question confirms that is a phospholipid. As it's structure contains hydrocarbon and phosphorus and might also contain nitrogen.

4 0
2 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
2 years ago
What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?
tankabanditka [31]
The molarity is the number of moles in 1 L of the solution. 
The mass of NH₃ given - 2.35 g
Molar mass of NH₃ - 17 g/mol
The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol
The number of moles in 0.05 L solution - 0.138 mol 
Therefore number of moles in 1 L - 0.138 mol / 0.05 L x 1L = 2.76 mol
Therefore molarity of NH₃ - 2.76 M
3 0
1 year ago
Read 2 more answers
The recommended daily intake of potassium ( K ) is 4.725 g . The average raisin contains 3.513 mg K . Fill in the denominators o
kondor19780726 [428]

Explanation:

It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.

             \frac{1 g}{1000 mg} or \frac{1000 mg}{1 g}

So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.

4 0
2 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
2 years ago
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