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AfilCa [17]
2 years ago
6

avogadro's number of representative particles is equal to one___. A) kilogram B)gram C)kelvin D)mole

Chemistry
2 answers:
a_sh-v [17]2 years ago
8 0

D

Avogadro's number allows us to measure the amount of atoms or molecules in one mole of a substance.

irina1246 [14]2 years ago
6 0

Answer:

Mole

Explanation:

Avagadro's number is the number of atoms, molecules, ions or any particle which is equal to 6.023X10²³.

A mole is the amount of substance which contains 6.023X10²³ number of atoms, molecules or ions.

For example 12g of carbon contains 6.023X10²³ number of atoms.

While kilogram and gram are units of mass.

kelvin is unit of temperature.

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What is the hydronium ion concentration of a solution whose pH is 7.30
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[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

hope this helps!
6 0
2 years ago
Functional group and bond hybridization of vanillin
lana66690 [7]

Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group:  R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

7 0
2 years ago
Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat
disa [49]
8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6
8 0
2 years ago
A voltaic cell is constructed with two silver-silver chloride electrodes, where the half-reaction is AgCl (s) + e− → Ag (s) + Cl
ANTONII [103]

Answer : The cell emf for this cell is 0.118 V

Solution :

The half-cell reaction is:

AgCl(s)+e^\rightarrow Ag(s)+Cl^-(aq)

In this case, the cathode and anode both are same. So, E^o_{cell} is equal to zero.

Now we have to calculate the cell emf.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cl^{-}{diluted}]}{[Cl^{-}{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 1

E_{cell} = ?

[Cl^{-}{diluted}] = 0.0222 M

[Cl^{-}{concentrated}] = 2.22 M

Now put all the given values in the above equation, we get:

E_{cell}=0-\frac{0.0592}{1}\log \frac{0.0222M}{2.22M}

E_{cell}=0.118V

Therefore, the cell emf for this cell is 0.118 V

4 0
2 years ago
What is the molarity of a solution that contains 0.500 mole of kno3 dissolved in 0.500-liter of solution?
belka [17]

Answer : The molarity of solution is, 1.00 M

Explanation : Given,

Moles of KNO_3 = 0.500 mol

Volume of solution = 0.500 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }KNO_3}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.500mol}{0.500L}=1.00mole/L=1.00M

Therefore, the molarity of solution is, 1.00 M

7 0
2 years ago
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