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1 year ago

Identify one disadvantage to each of the following models of electron configuration:

Chemistry

2 answers:

Murrr4er [49]1 year ago

6 0

Answer:

The disadvantages of each of the given model of electron configuration have been mentioned below:

1). Dot Structures - They take up excess space as they do not display the electron distribution in orbitals.

2). Arrow and line diagrams make the counting of electrons and take up too much space.

3). Written Configurations do not display the electron distribution in orbitals and help in lose counting of electrons easily.

Naddika [18.5K]1 year ago

5 0

Advantages:

-Dot structures make it easy to count electrons and they show the number of electrons in each electron shell.

-Arrow and line diagrams show the spin of electrons and show every orbital.

-Written configurations require minimal space and show the distribution of electrons between subshells.

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You are asked to go into the lab and prepare an acetic acid - sodium acetate buffer solution with a ph of 4.00  0.02. what mola

Oxana [17]

Hello!

To solve this problem we are going to use the Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is 4,76:

$pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )$

$\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75$

So, the mole ratio of CH₃COOH to CH₃COONa is 5,75

Have a nice day!

5 0

2 years ago

Iodine is 80% 127I, 17% 126I, and 3% 128I. Calculate the average atomic mass of Iodine.

trasher [3.6K]

<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>

Given

80% 127I, 17% 126I, and 3% 128I.

Required

The average atomic mass

Solution

The elements in nature have several types of isotopes

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%

Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128

Atomic mass of Iodine = 101.6 + 21.42 + 3.84

Atomic mass of Iodine = 126.86 amu

6 0

2 years ago

A heat energy of 645 J is applied to a sample of glass with a mass of 28.4 g. Its temperature increases from –11.6 ∞C to 15.5 ∞C

Anika [276]

The heat that is required to raise the temperature of an object is calculated through the equation,
heat = mass x specific heat x (T2 - T1)
Specific heat is therefore calculated through the equation below,
specific heat = heat / (mass x (T2 - T1))
Substituting,
specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The value of specific heat from above equation is 0.838 J/g°C.

5 0

2 years ago

A gas is initially at a pressure of 0.43 atm, and a volume of 11.7 liters. Then the pressure is raised to 3.61 atm and the volum

lukranit [14]

Answer:

D. 91.98K

Explanation:

The General Gas Law equation is given by,

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

From the question,

the initial pressure,

$P_1 = 0.43 \: atm$

the initial volume,

$V_1 = 11.7 \: litres$

the final temperature,

$T_2=627K$

the final pressure,

$P_2=3.61atm$

the final volume,

$V_2=9.5litres$

Making

$T_1$

the subject of the expression, we obtain

$T_1= \frac{P_1V_1T_2}{P_2V_2}$

By substitution,

$T_1= \frac{0.43 \times11.7 \times627}{3.61 \times9.5}$

$T_1=91.980K$

Hence the initial temperature was 91.98 K

4 0

1 year ago

Read 2 more answers

trans-2-Butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm-1); however, IR spectroscopy is

spayn [35]

Answer:

The other signal that would indicate the presence of a C= C bond appears close to 3100 $cm^{-1}$ .

Explanation:

Bands that appear above 3000 $cm^{-1}$ are often unsaturation diagnoses suggest. The band at 3000- 3100 $cm^{-1}$ is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.

4 0

1 year ago