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1 year ago

How much maleic anhydride would you need to react 178 mg of anthracene? Assume 1:1 ratio from maleic anhydride to anthracene.

Chemistry

1 answer:

Licemer1 [7]1 year ago

8 0

Answer:

(1) 0.10 (2) 17.8 g

Explanation:

Since the reaction ratio is 1:1 what we need is to convert the given masses to moles and you will have the answer:

MW anthracene = 178.23 g/mol

MW maleic anhydride = 98.06 g/mol

a) mass anthracene = 178 mg x 1 g/ 1000 mg = 0.178 g anthracene

Moles anthracene = 0.178 g anthracene/ 178.23 g/mol

= 0.001 mol anthracene

0.001 mol anthracene x 1 mol maleic acid/mol anthracene

= 0.001 mol maleic anhydride

mass maleic anhydride = 0.001 mol x 98.06 g/mol = 0.10 g

b) moles maleic anhydride = 9.8 g/ 98.06 g/mol = 0.099 moles

0.099 moles maleic anhydride x 1 mol anthracene/mol maleic anhydride =

0.099 mol anthracene

g anthracene = 0.10mol x 178 g/mol = 17.8 g

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A block of copper of unknown mass has an initial temperature of 65.4 degress celcuis. THe copper is immersed in a beaker contain

Zigmanuir [339]

Answer:

The answer to your question is: m = 37.88 g

Explanation:

Data

Copper Water

mass ? 95.7 g

Cp 0.092 cal/g°C 1 cal/g°C

T1 65.4°C 22.7°C

T2 24.2°C 24.2°C

Formula

Q copper = Q water

Q = mCp(T2 - T1)

- m(0.092)(24.2 - 65.4) = 95.7(1)(24.2 - 22.7)

m = 95.7(1)(24.2 - 22.7) /- (0.92)(24.2 - 65.4)

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2 years ago

What is the correct name for the ionic compound Ca2P5

maks197457 [2]

Answer:

It is calcium phosphide.

Explanation:

Calcium phosphide is a salt like material that is composed of calcium and phosphorus in the ratio of 2:5. It has the appearance of red brown Crystalline salt.

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It is also use in fire works.

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2 years ago

Read 2 more answers

Which of the following yields a basic solution when dissolved in water? I. Nh3 ii. Na2o iii. Lioh iv. P4o10

emmainna [20.7K]

Answer: The correct answer is Option 1, Option 2 and Option 3.

Explanation:

A base is defined as the substance which releases hydroxide ion when dissolved in water.

For the given options:

Option 1: $NH_3$

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$NH_3+H_2O\rightarrow NH_4OH$

Option 2: $Na_2O$

When sodium oxide is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

$Na_2O+H_2O\rightarrow 2NaOH$

Option 3: $LiOH$

When lithium hydroxide is dissolved in water, it produces aqueous lithium hydroxide which forms a basic solution.

$LiOH+H_2O\rightarrow LiOH(aq.)$

Option 4: $P_4O_{10}$

When phosphorus pentoxide is dissolved in water, it produces phosphoric acid which forms an acidic solution.

$P_4O_{10}+6H_2O\rightarrow 4H_3PO_4$

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2 years ago

What is the formula when the halogen from 3rd principal energy level combines with you alkaline earth metal from the 4th energy

Korvikt [17]

Answer: $CaCl_2$

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Halogen with n=3 is chlorine.

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$[Ca]=1s^22s^22p^63s^23p^64s^2$

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$[Cl]=1s^22s^22p^63s^23p^5$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]=1s^22s^22p^63s^23p^6$

Here $Ca^{2+}$ cation and chloride $Cl^{-}$ anion combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CaCl_2$ .

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1 year ago

Calculate the Ka for 0.220 M solution of H3AsO4, pH = 1.50

puteri [66]

Remember that the formula to calculare KA is the following
Ka = [H+ ion]*[conj. base] / [acid]
Now that you have the data you can do as the following:
Ka = [H+]*[base] / [acid] 
Ka = [x]*[x] / [acid - x] 
Ka = x^2 / [acid - x]
then we go
Ka = [.032]^2 / [.220 - .032]
Ka = 5.4 x 10^-3.
Or what is the same
Ka = .0054

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1 year ago