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Xelga [282]
2 years ago
15

The distinctive odor of vinegar is due to acetic acid, HC₂H₃O₂, which reacts with sodium hydroxide. If a 3.45 mL sample of vineg

ar needs 42.5 mL of 0.115 M NaOH to be neutralized, how many grams of acetic acid are in a 1.00 L bottle of this vinegar?​
Chemistry
1 answer:
Vilka [71]2 years ago
8 0

Answer:

Explanation:

CH₃COOH + NaOH = CH₃COONa + H₂O .

42.5 mL of .115 M of NaOH will contain .0425 x .115 moles of NaOH

= 48.875 x 10⁻⁴ moles NaOH

It will react with same number of moles of acetic acid

So number of moles of acetic acid in 3.45 mL = 48.875 x 10⁻⁴

number of moles of acetic acid in 1000 mL = 48.875 x 10⁻⁴ x 10³ / 3.45 moles

= 1.4167 moles

= 1.4167 x 60 gram

= 85 grams .

So 85 grams of acetic acid will be contained in one litre of acetic acid.

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<span>If we use 100 mL of solution:
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m(C</span>₂H₆O₂) = 52 mL · 1,115 g/mL = 57,98 g.<span>
n(C</span>₂H₆O₂) = 57,98 g ÷ 62,07 g/mol = 0,934 mol.<span>
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1 year ago
The lab procedure involves several factors, listed below. Some were variable and some were constant. Label each factor below V f
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Answer :

V - mass of the water in the calorimeter

V - mass of the metal

V - change in temperature of the water

V - change in temperature of the metal

C - volume of water in calorimeter

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Variables : It is a factor that changes during the experiment or calculation.

Constant : It is a factor that does not change during the experiment or calculation.

In a calorimeter, the heat absorbed is equal to the heat released.

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m_2 = mass of metal

\Delta T_1 = change in temperature of the water

\Delta T_2 = change in temperature of the metal

c_1 = specific heat of water

c_2 = specific heat of metal

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The volume of water in calorimeter, calorimeter pressure is also constant.

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The correct option is C.
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