Calculate the pH of a buffer solution prepared by dissolving 0.20 mole of cyanic acid (HCNO) and 0.80 mole of sodium cyanate (Na
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Answer:
C) 0.28 M
Explanation:
Considering:
Potassium hydroxide will furnish hydroxide ions as:
Given :
<u>For Potassium hydroxide : </u>
Molarity = 0.25 M
Volume = 40.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 40.0×10⁻³ L
Thus, moles of hydroxide ions furnished by Potassium hydroxide is same as the moles of Potassium hydroxide as shown below:
Moles of hydroxide ions by Potassium hydroxide = 0.01 moles
Barium hydroxide will furnish hydroxide ions as:
Given :
<u>For Barium hydroxide : </u>
Molarity = 0.15 M
Volume = 60.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 60.0×10⁻³ L
Thus, moles of hydroxide ions furnished by Barium hydroxide is twice the moles of Barium hydroxide as shown below:
Moles of hydroxide ions by Barium hydroxide = 0.018 moles
Total moles = 0.01 moles + 0.018 moles = 0.028 moles
Total volume = 40.0×10⁻³ L + 60.0×10⁻³ L = 100×10⁻³ L
Concentration of hydroxide ions is:
<u> The final concentration of hydroxide ion = 0.28 M</u>
Answer :
Standard enthalpy of formation : It is defined as the enthalpy change for the reaction that forms one mole of compound from its elements. All the substances in their standard states.
The balanced chemical equation for the reaction is,
In the balance reaction, Strontium (Sr), Carbon (C) and Strontium carbonate are in solid state and oxygen is in gaseous state.