Identify the TRUE statement.

Chemistry

1 answer:

xeze [42]2 years ago

4 0

Answer:

d. In a granite containing quartz, mica, and feldspar, everything weathers to clay except the quartz.

Explanation:

Granite is a rock formed by a set of minerals, but its composition is basically as follows: Quartz, a colorless mineral; Feldspar (orthoclase, sanidine and microcline), responsible for the variety of colors, including reddish, pink and cream-gray; and Mica (biotite and muscovite), which adds shine to the rock. Of these three minerals, mica and feldspar generate clay during the weathering process, however quartz does not generate clay, probably due to its hardness.

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The three‑dimensional structure of a generic molecule is given. Identify the axial and equatorial atoms in the three‑dimensional

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Answer:

Explanation:

CHECK THE ATTACHMENT FOR THE COMPLETE QUESTION AND THE DETAILED EXPLANATION

NOTE:

Equatorial atoms are referred to atoms that are attached to carbons in the cyclohexane ring which is found at the equator of the ring.

Axial atoms are atoms that exist in a bond which is parallel to the axis of the ring in cyclohexane

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Select the NMR spectrum that corresponds best to p-bromoaniline. (see Hint for the structure.) The selected tab will be highligh

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Answer:

The NMR spectrum that corresponds best to p-bromoaniline is the one that is attached in the image below.

Explanation:

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How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?

lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

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