Answer:
The specific heat of the metal is 0.466 
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
- Q= 2330 J
- c= ?
- m= 25 g
- ΔT= 200 °C
Replacing:
2330 J= c*25 g* 200 °C
Solving:
c=0.466
<u><em>The specific heat of the metal is 0.466 </em></u><u><em></em></u>
Superscript o subscript negative 1 e.
Explanation:
The nuclear reactions is of 2 types, one is nuclear fusion and the other one is nuclear fission.
Nuclear fusion is nothing but the combining of 2 nuclei with an emission of energy along with an electron, proton or beta particle.
Nuclear fission is the break down of a nucleus into 2 or more nuclei along with an electron, proton or beta particle.
And the reaction is,
₅₆B¹²⁴ ₅₅C¹²⁴ + ₋₁e⁰
So the blank was filled by means of a beta particle.
Hello!
Bases are defined by Arrhenius as substances which release OH⁻ ions when dissolved in water. NO₂⁻ complies with this definition by the chemical reaction that is shown below:
NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)
Have a nice day!
<span>In order to do this, you have change the alkene into an
alkyne. That is the aim of Br2/CH2Cl2 trailed by NaNH2. The Br2 with form a vic
dihalide (3,4-dibromo octane). Adding of NaNH2 will execute two E2 reactions.
-NH2 will eliminate an H from carbons 3 and 4. This double elimination will make
the alkyne. Then handling the alkyne with H2/Lindlar will form the cis alkene. The
final product will be CIS-3-octene.</span>
<span>The question says,'which statement best describes how an ionic bond forms. The correct option is A. Ionic bonds are formed as a result of complete transfer of electrovalence electrons from one atom to another. The atom that donate the electron become a positively charged ion while the atom that received the atom become a negatively charged ion.</span>
