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2 years ago

2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?

1 answer:

7 0

You did not include the options but I can tell you the product ratio.

The product ratio is the mole ratio of the products of the reaction.

From the balanced chemical equation you have all the mole ratios:

The given equation is: 2 C6H5COOH + 15O2 --> 14 CO2 + 6H2O

The mole ratios are: 2 C6H5COOH: 15 O2: 14 CO2 : 6 H2O

The products are CO2 and H2O

Their mole ratio = 14 CO2 : 6 H2O

That can be expressed as:

14 mol CO2        7 mol CO2
----------------- = -----------------
6 mol H2O        3 mol H2O

It is also the same that:

6 mol H2O : 14 mol CO2

6 mol H2O           3 mol H2O
------------------ = -------------------
14 mol CO2           7 mol CO2

So, compare your options to the ratios show above and pick the proper ratio.

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For each of the following substituents, indicate whether it withdraws electrons inductively, donates electrons by hyperconjugati

AveGali [126]

Answer:

a. withdraws electrons inductively

b. donates electrons by hyperconjugation

c. donates electrons by resonance

d. withdraws electrons inductively

Explanation:

a. The bromide ion is a highly electronegative ion (in the halide series). Electronegative substituents on acids increase the acidity by inductive electron withdrawal method. The higher the electronegativity of a substance, the greater the acidity. The halogens have this order of electronegativity:

F > Cl > Br>I

b. The carboxyl groups have a stabilization of the sigma and pi bonds. This is achieved through a special delocalization of electrons. Because of the delocalization, hyperconjugation is the result effect.

c. The NHCH₃ group has a highly electonegative nitrogen atom that pulls the electron cloud towards itself. In this case, it withdraws electrons inductively. As a result, it donates electrons by resonance.

d. The OCH₃ group has a highly electonegative oxygen atom. This oxygen atom withdraws electron cloud towards itself. As a result, it withdraws electrons inductively.

3 0

2 years ago

A piston containing 0.120moles of methane gas, CH4, has a volume of 2.12liters. If methane is added until the volume is increase

earnstyle [38]

Answer:

2.83 g

Explanation:

At constant temperature and pressure, Using Avogadro's law

$\frac {V_1}{n_1}=\frac {V_2}{n_2}$

Given ,

V₁ = 2.12 L

V₂ = 3.12 L

n₁ = 0.120 moles

n₂ = ?

Using above equation as:

$\frac{2.12}{0.120}=\frac{3.12}{n_2}$

$2.12n_2=0.12\cdot \:3.12$

$2.12n_2=0.3744$

$n_2=\frac{0.3744}{2.12}$

$n_2=0.17660$

n₂ = 0.17660 moles

Molar mass of methane gas = 16.05 g/mol

So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g

<u>2.83 g are in the piston.</u>

8 0

2 years ago

Jane made this picture to represent a chemical reaction: Two circles, one white and the other gray are shown on the left. A smal

7nadin3 [17]

It represents a decomposition reaction because one reactant breaks apart and forms two products.

Explanation:

The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.

In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.

XY → X + Y

Decomposition or cracking is the formation of two or more products from a single reactant.
The break down of a compound into individual atoms or molecules falls into this category.
The extreme instability of a compound drives such a reaction.
The products is usually stable or it can dissociate further till it is stable.

Find the image attached for more explanation:

Learn more:

Thermal decomposition brainly.com/question/11181911

#learnwithBrainly

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ivolga24 [154]

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