The atomic mass of a certain element is summation of the product of the decimal equivalent of the percentage abundance and the given atomic mass of each of the isotope. If we let x be the percentage abundance of the 86 amu-isotope then, the second one is 1-x such that,
x(86) + (1 - x)(90) = 87.08
The value of x from the equation is 0.73. This value is already greater than 0.5. Thus, the isotope with greatest abundance is that which is 86 amu.
The balance chemical equation is:
NaCH₃COO + HCl → NaCl + HCH₃COO
Make
Answer:
6.63
Explanation:
From the relationship;
pH = pKw/2
Pkw = 13.26
Then it follows that;
pH = 6.63
Hence if. pKw = 13.26, the pH = 6.63
Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
A negative formation enthalpy means that the reaction is exothermic, or that heat is released during the process.
(C,)
