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2 years ago

86.1 g of nitrogen reacts with lithium, how many grams of lithium will react?

Chemistry

1 answer:

Zina [86]2 years ago

4 0

Answer:

128g of Li, will react in this reaction

Explanation:

Before to start working, we need the reaction:

N₂ and Li react, in order to produce Li₃N (lithium nitride)

N₂ + 6Li → 2Li₃N

1 mol of nitrogen reacts with 6 moles of lithium

We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles

1 mol of N₂ reacts with 6 mol of Li

Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li

We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g

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Draw the best lewis structure for bro4- and determine the formal charge on bromine

Svetach [21]

Answer :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The electrons are represented by dot.

The given molecule is, perbromate ion.

Bromine has '7' valence electrons and oxygen has '6' valence electron.

Therefore, the total number of valence electrons in perbromate ion, $BrO_4^-$ = 7 + 4(6) + 1 = 32

According to Lewis-dot structure, there are 14 number of bonding electrons and 18 number of non-bonding electrons.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on }Br=7-0-\frac{14}{2}=0$

The Lewis-dot structure of perbromate ion is shown below.

7 0

2 years ago

Read 2 more answers

Determine the number of atoms in 1.85 ml of mercury. (the density of mercury is 13.5 g/ml.)

kati45 [8]

First step is to get the mass of the mercury:
Pressure = mass/volume
mass = pressure x volume = 13.5 x 1.85 = 24.975 gm

Second step is to calculate the number of moles in 24.975 gm:
From the periodic table, the molar mass of mercury is 200.59
mass = number of moles x molar mass
number of moles = 24.975 / 200.59 = 0.1245 mole

Last step is to get the number of atoms:
Each mole contains 6.02 x 10^23 atoms
number of atoms = 0.1245 x 6.02 x 10^23 = 7.4949 x 10^22 atoms

7 0

2 years ago

The adult blue whale has a lung capacity of 5.0×103 L5.0×103 L. Calculate the mass of air (assume an average molar mass 28.98 g/

andrew11 [14]

Answer:

The mass of the air is 6920.71g

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Volume (V) = 5.0x10^3 L

Molar Mass of air (M) = 28.98 g/mol

Temperature (T) = 0.2°C

Pressure (P) = 1.07 atm

mass air (m) =?

Number of mole (n) =?

Recall:

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Conversion of celsius temperature to Kelvin temperature.

K = °C + 273

°C = 0.2°C

K = °C + 273

K = 0.2°C + 273

K = 273.2 K

Therefore, the temperature (T) = 273.2 K

Step 3:

Determination of the number of mole of air.

Applying the ideal gas equation PV = nRT, the number of mole n, can be obtained as follow:

PV = nRT

1.07 x 5.0x10^3 = n x 0.082 x 273.2

Divide both side by 0.082 x 273.2

n = (1.07 x 5.0x10^3)/(0.082 x 273.2)

n = 238.81 moles

Step 4:

Determination of the mass of air. This is illustrated below:

Number of mole of air = 238.81 moles

Molar Mass of air = 28.98 g/mol

Mass of air =.?

Mass = number of mole x molar Mass

Mass of air = 238.81 x 28.98

Mass of air = 6920.71g

3 0

2 years ago

Identify the precipitate (if any) that forms when nach3coo (also written as nac2h3o2) and hcl are mixed. express your answer as

Karolina [17]

When NaCH3Coo mixed with HCl we will get NaCl and CH3CooH as shown in the following balanced equation:

NaCH3Coo + HCl → NaCl + CH3CooH
so from this equation, we can conclude that is no precipitate because all we get is the acetic acid which found in vinegar and the NaCl which is very soluble so we don't have any precipitate.
so, your answer is no precipitate, no reaction

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2 years ago

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Alinara [238K]

Answer:

$\%\ Composition\ of\ iron=69.92\ \%$