Answer:
here ya go trust
Explanation:
Commercially available hot packs are simple in design: a pouch with water on one side, isolated by a barrier from a specific sal
1 answer:
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Answer:
NH₃/NH₄Cl
Explanation:
We can calculate the pH of a buffer using the Henderson-Hasselbalch's equation.
If the concentration of the acid is equal to that of the base, the pH will be equal to the pKa of the buffer. The optimum range of work of pH is pKa ± 1.
Let's consider the following buffers and their pKa.
- CH₃COONa/CH3COOH (pKa = 4.74)
- NH₃/NH₄Cl (pKa = 9.25)
- NaOCl/HOCl (pKa = 7.49)
- NaNO₂/HNO₂ (pKa = 3.35)
- NaCl/HCl Not a buffer
The optimum buffer is NH₃/NH₄Cl.
3.98 x 10⁻¹⁹ Joule
<h3>Further explanation</h3><u>Given:</u>
The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.
<u>Question:</u>
The energy of a photon of green light (in joules).
<u>The Process:</u>
The energy of a photon is given by
- E = energy in joules
- h = Planck's constant 6.63 x 10⁻³⁴ Js
- f = frequency of light in Hz (sometimes the symbol f is written as v)
Let us find out the energy of the green light emitted per photon.
Thus, we get a result of
- - - - - - - - - -
Notes
- When an electron moves between energy levels it must emit or absorb energy.
- The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
- A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
- The energy of the orange light emitted per photon brainly.com/question/2485282#
- Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
- Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146
Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules
Answer:
ν = 7.04 × 10¹³ s⁻¹
λ = 426 nm
It falls in the visible range
Explanation:
The relation between the energy of the radiation and its frequency is given by Planck-Einstein equation:
E = h × ν
where,
E is the energy
h is the Planck constant (6.63 × 10⁻³⁴ J.s)
ν is the frequency
Then, we can find frequency,
Frequency and wavelength are related through the following equation:
c = λ × ν
where,
c is the speed of light (3.00 × 10⁸ m/s)
λ is the wavelength
A 426 nm wavelength falls in the visible range (≈380-740 nm)