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aleksandrvk [35]
2 years ago
5

Calculate the average time it took the car to travel 0.25 What is the average time it took the car to travel 0.25

Chemistry
2 answers:
DedPeter [7]2 years ago
8 1

Answer:

Explanation:

idk why all u guys like trump who do.. hes just a big pain in the a*s.

Guest
1 year ago
shut the f*ck up this is for work not your bullsh*t
Guest
1 year ago
biden is a f*cking dumb b*tch im only a child and i can run a country better than his old slow 2 mph walking a*s
yawa3891 [41]2 years ago
4 0

Answer:

2.23 3.13

Explanation:

just did it

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What is the melting point of tert-butanol? Besides using a heat lamp, what other options might there be for dispensing a given a
damaskus [11]

Answer:

For dispensing, weigh it out.

Yes, a different solvent such as ethanol could be used.

Explanation:

Besides using various methods for melting the <em>tert</em>-butanol in order to pour it out and measure a given volume, the <em>tert</em>-butanol could be weighed out in a beaker using a scale. Depending on the temperature of the laboratory, the <em>tert</em>-butanol could be a solid or a liquid/solid mixture.

In general, a different solvent such as ethanol could be used in place of <em>tert</em>-butanol as long as the solvent is a low molecular weight alcohol.

6 0
2 years ago
According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution? Assume that ther
IgorC [24]

Answer:

0.020 moles of Fe(OH)_{2} can be formed

Explanation:

1. First determine the number of moles of LiOH.

Molarity is given by the following expression:

M=\frac{molesofsolute}{Litersofsolution}

Solving for moles of solute:

moles of solute = M * Liters of solution

Converting 175.0mL to L:

175.0mL*\frac{1L}{1000mL}=0.175L

Replacing values:

moles of solute = 0.227M*0.175L

moles of solute = 0.040

Therefore there are 0.040 moles of LiOH

2. Then write the balanced chemical reaction and use the stoichiometry of the reaction to calculate the number of moles of Fe(OH)_{2} produced:

FeCl_{2}(aq)+2LiOH(aq)=Fe(OH)_{2}(s)+2LiCl(aq)

As the problem says that there are excess of FeCl_{2}, the limiting reagent is the LiOH.

0.040molesLiOH*\frac{1molFe(OH)_{2}}{2molesLiOH}=0.020molesFe(OH)_{2} can be formed

3 0
2 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
2 years ago
Oxygen at 150 k and 41.64 atm has a tabulated specific volume of 4.684 cm3/g and a specific internal energy of 1706 j/mol. calcu
docker41 [41]

The total energy in a system due to the temperature and pressure per unit mass in that system is known as specific enthalpy. It is used in thermodynamic equations when one desires to know the energy for a given single unit mass of a component.  

Specific enthalpy is calculated by the equation:  

H = U + PV

in the given case, Specific volume = 4.684 cm³/g = 149.888 cm³/g moles = 149.888 × 10⁻³ J/g moles

Specific internal energy (U) is 1706 J/mol and pressure is 41.64.  

H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules  

= 2428 joules / mole


5 0
2 years ago
How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required
cupoosta [38]

Answer:

88.8 minutes

Explanation:

Graham's law of diffusion relates rate of difusion by the following formula

Rate1 / rate 2 = √( Mass of argon / Mass of Neon)

Where rate = volume divided by time

Rate 1 = 10 ml / t1

Rate 2 = 10 ml / t2

Rate 1/ rate 2 = 10 ml / t1 ÷ 10 ml/ t2 = t2/ t1

t2/t1 = √(Mass of argon / mass of Neon) = √( 39.984/20.179)

125 / t1 = 1.4026

t1 = 125 / 1.4026 = 88.8 minutes

7 0
2 years ago
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