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Sliva [168]
2 years ago
15

A 0.5 mol sample of He(g) and a 0.5 mol sample of Ne(g) are placed separately in two 10.0 L rigid containers at 25°C. Each conta

iner has a pinhole opening. Which of the gases, He(g) or Ne(g), will escape faster through the pinhole and why?
A) He because the He atoms are moving at a higher average speed than the Ne atoms.
B) Ne because its initial pressure in the container is higher
C) Ne because the Ne atoms have a higher average kinetic energy than the He atoms
D) Both gases will escape at the same rate because the atoms of both gases have the same average kinetic enery
Chemistry
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

A) He because the He atoms are moving at a higher average speed than the Ne atoms.

Explanation:

The expression for the mean speed is:

C_{avg}=\sqrt {\dfrac{8RT}{\pi M}}

R is Gas constant having value = 8.314 J / K mol  

M is the molar mass of gas

T is the temperature

Thus, as seen from the formula,  

The average speed of the gas is inversely proportional to the square root of the molar mass of the gas

So, Helium has lower molecular mass than neon and thus, The speed of the sound in helium is greater when compared to that of neon.

<u>Thus, He will escape faster through the pinhole.</u>

<u>Option A. is correct.</u>

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What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water (Kf = 1.86C/(mol/kg) for water and
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4 0
2 years ago
Read 2 more answers
Given equilibrium partial pressures of PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm calculate the equilibrium constant
maxonik [38]
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.

In present case, following reaction is involved:

                        2NO2    ↔      2NO + O2

Here, K = \frac{[PNO]^2[O2]}{[PNO2]^2}

Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence,  K = \frac{[0.0022]^2[0.0011]}{[0.247]^2}
                 = 8.727 X 10^-8

Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................

Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.

Therefore, Reaction quotient = </span>\frac{[PNO]^2[O2]}{[PNO2]^2}
                                              = \frac{[0.021]^2[0.037]}{[0.192]^2}
                                              = 4.426 X 10^-4.

Here, Reaction quotient > Equilibrium constant.

Hence, <span>the reaction need to go to reverse direction to reattain equilibrium </span>
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2 years ago
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