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Sliva [168]
2 years ago
15

A 0.5 mol sample of He(g) and a 0.5 mol sample of Ne(g) are placed separately in two 10.0 L rigid containers at 25°C. Each conta

iner has a pinhole opening. Which of the gases, He(g) or Ne(g), will escape faster through the pinhole and why?
A) He because the He atoms are moving at a higher average speed than the Ne atoms.
B) Ne because its initial pressure in the container is higher
C) Ne because the Ne atoms have a higher average kinetic energy than the He atoms
D) Both gases will escape at the same rate because the atoms of both gases have the same average kinetic enery
Chemistry
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

A) He because the He atoms are moving at a higher average speed than the Ne atoms.

Explanation:

The expression for the mean speed is:

C_{avg}=\sqrt {\dfrac{8RT}{\pi M}}

R is Gas constant having value = 8.314 J / K mol  

M is the molar mass of gas

T is the temperature

Thus, as seen from the formula,  

The average speed of the gas is inversely proportional to the square root of the molar mass of the gas

So, Helium has lower molecular mass than neon and thus, The speed of the sound in helium is greater when compared to that of neon.

<u>Thus, He will escape faster through the pinhole.</u>

<u>Option A. is correct.</u>

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The solubility of CaCl2 in water is 25g per 50 mL of H2O. How many grams of CaCl2 will dissolved to form a saturated solution in
Natasha2012 [34]

Answer: option B. 5g

Explanation:

50mL of H2O dissolves 25g of CaCl2.

Therefore, 10mL of H2O will dissolve Xg of CaCl2 i.e

Xg of CaCl2 = (10 x 25) /50 = 5g

8 0
2 years ago
Why is it advisable to wear long sleeves when students work in a chemistry lab? to provide warmth near the lab refrigerator to p
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2 years ago
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An equimolar mixture of N2(g) and Ar(g) is kept inside a rigid container at a constant temperature of 300 K. The initial partial
andrey2020 [161]

Answer:

The final pressure of the gas mixture after the addition of the Ar gas is P₂= 2.25 atm

Explanation:

Using the ideal gas law

PV=nRT

if the Volume V = constant (rigid container) and assuming that the Ar added is at the same temperature as the gases that were in the container before the addition, the only way to increase P is by the number of moles n . Therefore

Inicial state ) P₁V=n₁RT

Final state )  P₂V=n₂RT

dividing both equations

P₂/P₁ = n₂/n₁ → P₂= P₁ * n₂/n₁

now we have to determine P₁ and n₂ /n₁.

For P₁ , we use the Dalton`s law , where p ar1 is the partial pressure of the argon initially and x ar1 is the initial molar fraction of argon (=0.5 since is equimolar mixture of 2 components)

p ar₁ = P₁ * x ar₁  →  P₁ = p ar₁ / x ar₁ = 0.75 atm / 0.5 = 1.5 atm

n₁ = n ar₁ + n N₁ =  n ar₁ + n ar₁ = 2 n ar₁

n₂ = n ar₂ + n N₂ = 2 n ar₁ + n ar₁ = 3 n ar₁

n₂ /n₁ = 3/2

therefore

P₂= P₁ * n₂/n₁ = 1.5 atm * 3/2  = 2.25 atm

P₂= 2.25 atm

8 0
2 years ago
50cm3 of sodium hydroxide solution was titrated against a solution of sulfuric acid. The concentration of the sodium hydroxide s
miskamm [114]

Answer:

49 g/L is the concentration of the acid

Explanation:

Firstly, we proceed to write the equation of reaction.

2NaOH + H2SO4 ——-> Na2SO4 + 2H2O

We can see that 1 mole of the base reacted with two moles of the acid.

kindly note that dm^3 is same as liter

Firstly, we need to get the concentration of the reacted sulphuric acid in g/L

we use the simple titration equation below;

CaVa/CbVb = Na/Nb

From the question;

Ca = ?

Va = 25 cm^3

Cb = 20 g/L

we convert this to concentration in mol/L

Mathematically, that is concentration in g/L divided by molar mass in g/mole

molar mass of NaOH = 40 g/mol

so we have; 20g/L / 40 = 0.5 mol/L

Vb = 50 cm^3

Na = 1

Nb = 2

Where C represents concentrations, V volumes and N , number of moles

Now, substitute the values;

Ca * 25/0.5 * 50 = 1/2

25Ca/25 = 0.5

So Ca = 0.5 mol/L

Now to get the concentration of H2SO4 in g/L

What we do is to multiply the concentration in mol/L by molar mass in g/mol

That would be 0.5 * 98 = 49 g/L

4 0
2 years ago
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erma4kov [3.2K]

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<u>Explanation</u>:

  • The reaction between an acid and a base is known as a neutralization reaction. The reaction of an acid with a base to give salt, water and heat is called neutralization.
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  • The heat evolved in the neutralization reaction raises the temperature of the reaction mixture.    
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1 year ago
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