Smaller atoms ; free neutrons and energy
Answer:
A) 3.59 cm
Explanation:
Given that :-
The density of the gold ingot = 
Given that:- Mass = 5.50 lbs
Also, considering the conversion of lbs to g as shown below:-
1 lb = 453.592 g
Thus,
Mass = 
= 2494.756 g
The volume = Length*Breadth*Height
Given that:- Length = 12.0 cm , Breadth = 3.00 cm
Considering the expression for density as:-
Solving for height, we get that:-
Height=3.59 cm
Answer:
3.43 %
Explanation:
We need to calculate first the number of moles of CeO2 produced in the combustion. Given its formula we know how many moles of Ce atom are present. From there calculate the mass this number of moles this represent and then one can calculate the percentage.
0.1848 g CeO2 x 1 mol CeO2/172.114g = 0.00107 mol CeO2
0.00107 mol CeO2 x 1 mol Ce/ 1 mol CeO2 = 0.00107 mol Ce
.00107 mol Ce x 140.116 g Ce/ mol = 0.150 g Ce
0.150 g Ce/ 4.3718 g sample x 100 = 3.43 %
Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
