Pressure of argon = 546.8 kPa
Conversion factor: 1 atm = 101.325 kPa
Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm
Moles of argon = 15.82
Volume of argon = 75.0 L
According to Ideal gas law,
PV = nRT
where P is the pressure, V is the volume , n is the number of moles, R is the universal gas constant, and T is the temperature
T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)
T = 311.82 K
Hence the temperature of the canister is 311.82 K.
Answer:
Micky Mo is suffering from respiratory acidosis.
Explanation:
The pCO2 level in micky"s body is higher than normal it means the excess amount of CO2 will reacts with water to generate carbonic acid(H2CO3).
On the other hand according to the question total HCO3- also higher than normal.As a result the excess HCO3- will react with proton to form carbonic acid which is in turn dissociate to generate CO2 and H2O to maintain normal acid base homeostasis.
From that point of view it can be said Micky Mo is suffering from respiratory acidosis.
Answer:
7.46 g
Explanation:
From the balanced equation, 2 moles of Mg is required for 2 moles of MgO.
The mole ratio is 1:1
mole = mass/molar mass
mole of 4.50 g Mg = 4.50/24.3 = 0.185 mole
0.185 mole Mg will tiled 0.185 MgO
Hence, theoretical yield of MgO in g
mass = mole x molar mass
0.185 x 40.3 = 7.46 g
Mass of medicinal agent taken = 1.2 g
the volume is 60 mL
Specific gravity = 1.20
So the mass of solution = specific gravity X volume = 1.20 * 60 = 72g
Now if we have increased the volume by 0.2 so the new volume = 60.2
New mass = 72 + 1.2 = 73.2
Specific gravity = mass / volume = 73.2 / 60.2 = 1.22 g/mL
<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles
<u>Explanation:</u>
The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.
The equation used to calculate number of moles is given by:
where,
are the initial volume and number of moles
are the final volume and number of moles
We are given:
Putting values in above equation, we get:
Hence, the number of moles of gas remaining in the lungs is 0.063 moles
