Devon’s laboratory is out of material to make phosphate buffer. He is considering using sulfate to make a buffer instead. The pk
1 answer:
You might be interested in
Answer:
1) Net ionic equation :
2) 0.765 M is the molarity of the carbonic acid solution.
Explanation:
1) In aqueous carbonic acid , carbonate ions and hydrogen ion is present.:
..[1]
In aqueous potassium hydroxide , potassium ions and hydroxide ion is present.:
..[2]
In aqueous potassium carbonate , potassium ions and carbonate ion is present.:
..[3]
From one:[1] ,[2] and [3]:
Cancelling common ions on both sides to get net ionic equation :
2)
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
0.765 M is the molarity of the carbonic acid solution.
Answer:
78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene
Explanation:
Moles of propene =
According to reaction, 1 mole of propene gives 1 mole of propane.
Then 0.6538 moles of bromo-propane will give:
78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.
Answer:- selenium, Se.
Explanations:- When an element gain electrons then it becomes negatively charged means it forms it's anion. Total electrons of the anion are the sum of electrons and the charge of the anion. In our problem, the element is q and it forms ion. The Total electrons for the anion
= electrons of q + 2
As per the given info, there are 36 electrons in ion.
So, 36 = electrons of q + 2
electrons of q = 36 - 2
electrons of q = 34
q, the neutral atom has 34 electrons means it's atomic number is 34. If we check out the periodic table then the element with atomic number 34 is Selenium, Se.