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siniylev [52]
2 years ago
7

Devon’s laboratory is out of material to make phosphate buffer. He is considering using sulfate to make a buffer instead. The pk

a values for the two hydrogens in H2SO4 are -10 and 2.
Will this approach work for making a buffer effective near a pH of 7?
O yes
O not enough information to answer
O no
What is the optimal pH for sulfate‑based buffers? Enter your answer as a whole number.
Chemistry
1 answer:
sesenic [268]2 years ago
4 0

Answer:

Is not possible to make a buffer near of 7.

Optimal pH for sulfate‑based buffers is 2.

Explanation:

The dissociations of H₂SO₄ are:

H₂SO₄ ⇄ H⁺ + HSO₄⁻ pka₁ = -10

HSO₄⁻ ⇄ H⁺ + SO₄²⁻ pka₂ = 2.

The buffering capacity is pka±1. That means that for H₂SO₄ the buffering capacity is in pH's between <em>-11 and -9 and between 1 and 3</em>, having in mind that pH's<0 are not useful. For that reason, <em>is not possible to make a buffer near of 7.</em>

The optimal pH for sulfate‑based buffers is when pka=pH, that means that optimal pH is <em>2.</em>

<em />

I hope it helps!

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Calculate the mass percent of Cl in Freon -112 (C2 Cl4 F2), a CFC refrigerant
Karolina [17]

Answer:

The answer to your question is:  69.6 %

Explanation:

Freon -112 (C₂Cl₄F₂)

MW = (12 x 2) + (35.5 x 4) + (19 x 2)

      = 24 + 142 + 38

      = 204 g

                       204 g of C₂Cl₄F₂  -----------------  100%

                       142 g                     -----------------   x

                      x = (142 x 100 ) / 204

                      x = 69.6 %

5 0
2 years ago
Read 2 more answers
The Lewis structure for CO2 has a central The Lewis structure for C O 2 has a central blank atom attached to blank atoms.
kirza4 [7]

Answer:

See the explanation

Explanation:

1) The Lewis structure for  CO_2 has a central Carbon<em> </em>atom attached to Oxygen atoms.

In the CO_2  we will have a structure:  O=C=O the <u>central atom</u> "carbon" we will have <u>2 sigma bonds and 2 pi bonds</u>, therefore, we have an <u>Sp hybridization</u>. For O we have <u>1 pi and 1 sigma bond</u>, therefore, we have an <u>Sp2 hybridization</u>.

2) These atoms are held together by <u>double bonds.</u>

<u></u>

Again in the structure of CO_2: O=C=O we only have double bonds.

3. Carbon dioxide has a Carbon dioxide has a <u>Linear</u> electron geometry.

Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.

4. The carbon atom is <u>Sp</u> hybridized.

We will have for carbon 2 pi bonds, so we will have an <u>Sp</u> hybridization.

5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.

(See figures)

Figure 1: Carbon hybridization

Figure 2: Oxygen hybridization

6 0
2 years ago
Element z reacts with bromine to form an ionic compound zbr2
slamgirl [31]

Explanation:

<u>Physical properties of ZBr₂</u>

The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:

  • it is a hard solid usually with high melting points or a liquid with high boiling points.
  • Soluble in water and insoluble in non-polar solvents.
  • It can conduct electricity in aqueous solutions or in molten form.
  • it will undergo a fast reaction.

<u>Z is a metal</u>

To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.

<u>Formula of the oxide</u>

ZO

                 Z                           0

                +2                         -2

It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.

Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.

Learn more:

ionic compounds brainly.com/question/6071838

#learnwithBrainly

               

5 0
2 years ago
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Andreas93 [3]

Answer :

Ethanol (C_2H_5OH) act as reducing agent.

The smallest possible integer coefficient of MnO_4^- in the combined balanced equation is, 4

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : C_2H_6O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

  • Now balance oxygen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • Now balance hydrogen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

Reduction : MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O

  • Now balance the charge.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In order to balance the electrons, we multiply the oxidation reaction by 5 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 5C_2H_6O+5H_2O\rightarrow 5C_2H_4O_2+20H^++20e^-

Reduction : 4MnO_4^-+32H^++20e^-\rightarrow 4Mn^{2+}+16H_2O

The balanced chemical equation in acidic medium will be,

5C_2H_6O+4MnO_4^-+12H^+\rightarrow 5C_2H_4O_2+4Mn^{2+}+11H_2O

In the redox reaction ethanol act as reducing agent and permanganate ion act as an oxidizing agent.

4 0
2 years ago
Freon-11, CCl3F has been commonly used in air conditioners. It has a molar mass of 137.35 g/mol and its enthalpy of vaporization
PilotLPTM [1.2K]

Answer:

180.56 Kilo joules of energy is removed in the form of heat when 1.00 kg of freon-11 is evaporated.

Explanation:

Molar mass of freon-11 = 137.35 g/mol

Enthalpy of vaporization of freon-11= \Delta H_{vap}=24.8 kJ/mol

Mass of freon-11 evaporated = 1.00 kg = 1000 g

Moles of freon-11 evaporated = \frac{1000 g}{137.35 g/mol}=7.2807 mol

Energy in the form of heat removed when 1.00 kg of freon-11 gets evaporated:

7.28067 mol\times \Delta H_{vap}=7.2807 mol\times 24.8 kJ/mol

=180.56 kJ

0 0
2 years ago
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