<span>MoO2
First, lookup the atomic weights of the elements involved
Atomic weight molybdenum = 95.94
Atomic weight oxygen = 15.999
Now calculate the molar mass of Mo2O3
2 * 95.94 + 3 * 15.999 = 239.877 g/mol
Now determine how many moles of the original Mo2O3 you had
10.63 g / 239.877 g/mol = 0.044314378 mol
Determine how much oxygen was added
11.340 g - 10.63 g = 0.71 g
How many moles of oxygen was added
0.71 g / 15.999 g/mol = 0.044377774 mol
Looking at the number of moles of oxygen added and the number of moles of the original compound, they're the same. So 1 oxygen atom was added to each molecule. Since the formula was Mo2O3, the new formula becomes Mo2O4. But since you're looking for the empirical formula, you need to reduce it. Both 2 and 4 are evenly divisible by 2, so the empirical formula becomes MoO2</span>
The balloon will reach its maximum volume and it will burst.
Given:
- A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
- When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
- The maximum volume of the weather balloon is 835 L.
To find:
Whether the weather balloon will reach its maximum volume or not.
Solution:
The pressure of the gas in the weather balloon at sea level = 

The volume of the weather balloon at sea level = 
The temperature of the gas in the weather balloon at sea level:

The balloon rises to an altitude.
The pressure of the gas in the weather balloon at the given altitude:

The volume of the weather balloon at the given altitude = 
The temperature of the gas in the weather balloon at the given altitude:

Using the Combined gas law:

The maximum volume of the weather balloon= V = 835 L

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.
Learn more about the combined gas law:
brainly.com/question/13154969?referrer=searchResults
brainly.com/question/936103?referrer=searchResults
Answer:
Explanation:
Entropy change in the system : --
ΔG = −54 kJ⋅mol−1 (−13 kcal⋅mol−1) = −54 kJ⋅mol−1 (−13 x 4.2 kJ⋅mol−1)
= - 108.6 KJ / mol
ΔH = -251 kJ/mol (-60 kcal/mol) = -251 kJ/mol (-60 x 4.2 kJ/mol)
= - 503 KJ / mol
ΔG = ΔH - TΔS
ΔS = ( ΔH - ΔG ) / T
= - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹
= - 1323.48 J / mol k⁻¹
Entropy change in the surrounding
+ 1323.48 J / mol k⁻¹
273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit