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S_A_V [24]
2 years ago
8

Which three temperature readings all mean the same thing? Question options: 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

373 Kelvin, 100 degrees Celsius, 273 degrees Fahrenheit 100 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit 273 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit
Chemistry
2 answers:
marta [7]2 years ago
8 0
<h3><u>Answer;</u></h3>

273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

<h3><u>Explanation;</u></h3>

<em>Kelvin, degrees Celsius and degrees Fahrenheit, all are units that may be used to measure temperature.</em>

Each unit may be converted to another using the following formulas.

  • °C = (°F - 32) × 5 / 9
  • °F = (°C ×1.8) + 32
  • K = °C + 273.0
  • °C = K - 273.0

Which means 0 °C is equivalent to 273 Kelvin, (K = °C + 273.0) and also equivalent to 32 degrees Fahrenheit (°F = (°C ×1.8) + 32 ).

shtirl [24]2 years ago
4 0
273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
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An enzyme with molecular weight of 310 kDa undergoes a change in shape when the substrate binds. This change can be characterize
oee [108]

Answer:

(a) r = 6.26 * 10⁻⁷cm

(b) r₂ = 6.05 * 10⁻⁷cm

Explanation:

Using the sedimentation coefficient formula;

s =  M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle

s = M ( 1 - Vρ) / N*6πnr

making r sbjct of formula, r =  M (1 - Vρ) / N*6πnrs

Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s

r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)

r = 6.26 * 10⁻⁷cm

b. Using the formula r₂/r₁ = s₁/s₂

s₂ = 0.035 + 1s₁ = 1.035s₁

making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁

r₂ = 6.3 * 10⁻⁷cm / 1.035

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8 0
2 years ago
A student wants to conduct an experiment to find out how pulse rate changes as the length of time spent exercising increases the
tester [92]

Answer:

I'm not 100% percent sure what your question is, but  here is what I think you are asking.

Explanation:

The dependent variable is pulse rate and the indepedent variable is the amount of exericse. The dependent variable changes as the independnet variable changes.

3 0
1 year ago
Two students are working together to build two models. Both models will represent the molecular structure of sodium bicarbonate,
vfiekz [6]

Answer:

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>

Explanation:

Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.

Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

8 0
1 year ago
When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and
Vika [28.1K]
The correct answer is 1. Lose electrons and become positive ions.


I hope my answer was beneficial to you! c:
5 0
2 years ago
Read 2 more answers
150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in
Kamila [148]
The chemical reaction would be written as 

2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
We use the given amounts of the reactants to first find the limiting reactant. Then use the amount of the limiting reactant to proceed to further calculations.

150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
180 g CCl4 (1 mol / 153.82 g) = 1.17 mol CCl4

 Therefore, the limiting reactant would be CCl4 since it would be consumed completely. The theoretical yield would be:

1.17 mol CCl4 ( 3 mol CCl2F2 / 3 mol CCl4 ) = 1.17 mol CCl2F2

7 0
1 year ago
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