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svetlana [45]
1 year ago
7

When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and

become negative ions 3. gain electrons and become positive ions 4. gain electrons and become negative ions?
Chemistry
2 answers:
Vika [28.1K]1 year ago
5 0
The correct answer is 1. Lose electrons and become positive ions.


I hope my answer was beneficial to you! c:
Andrews [41]1 year ago
4 0

Answer:

1) lose electrons and become positive ions

Explanation:

To be able to solve this question, it is crucial to understand generally the chemistry of metals and non metals.

Generally metals are found in groups 1,2,3 in the periodic table. What these  tells us is that they have 1,2,3 electrons in their outermost shells. whenever metals want to go into reactions to complete their octet, it is much more feasible energy wise to lose those few electrons than accept about 5,6,7 more electrons.

When a compound loses its electron(s), it becomes a positive ion due to the net increase of protons compared to electrons.

For instance, calcium has 20 electrons and protons. However when it loses 2 electrons to complete its octet and become Ca2+, it still retains its 20 protons but the total number of electrons left is 20 -2 = 1 8. The difference between the protons and the electrons is usually what is represented by the charge on the ion.

However, the reverse is the case when it comes to nonmetals. Non metals would rather accept the few electrons as it is much feasible energy wise to complete its octet. Also, when  non metals gain electrons they would become negative ions due to the excess in number of electrons compared to protons.

As such, the only logical answer would be 1) lose electrons and become positive ions.

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Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)×\frac{1molZn}{65,38g}×\frac{1molH_{2}(g)}{1molZn} = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL×\frac{101,325}{1atmL} = <em>19,26 kJ</em>

I hope it helps!

5 0
2 years ago
A solution contains 10.0 g pentane, C5H12, 20.0 g hexane, C6H14, and 10.0 g benzene, C6H6. What is the mole fraction of hexane?
GREYUIT [131]

Answer:

b) 0.47

Explanation:

MwC5H12 = 72.15g/mol

⇒mol C5H12 = (10.0)*(mol/72.15)=0.1386molC5H12

MwC6H14=86.18g/mol

⇒molC6H14=(20.0)*(mol/86.18)=0,232

MwC6H6=78.11g/mol

⇒molC6H6=(10.0)*(mol/78.11)=0.128molC6H6

<h3>XC6H14=(0.232)/(0.1386+0.232+0,128)=0.465≅0.47</h3>
7 0
2 years ago
All of the following reactions can be described as displacement reactions except:____________.
Lady_Fox [76]

Answer:

b

Explanation:

The reaction that is not a displacement reaction from all the options is C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>

Correct option = b.

8 0
1 year ago
How many moles are in 8.30x10^23 molecules of H2o
LUCKY_DIMON [66]
You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
=1.357*10^25

That should be the right answer but I'm not sure. It has been awhile since I have done this.

4 0
1 year ago
Read 2 more answers
6. From the values of ΔH and ΔS, predict which of the following reactions would be spontaneous at 25ºC: Reaction A: ΔH = 10.5 kJ
qwelly [4]

Answer:

Both reaction A and reaction B are non spontaneous.

Explanation:

For a spontaneous reaction, change in gibbs free energy (\Delta G) should be negative.

We know, \Delta G=\Delta H-T\Delta S, where T is temperature in Kelvin scale.

Reaction A: \Delta G=(10.5\times 10^{3})-(298\times 30)J/mol=1560J/mol

As \Delta G is positive therefore the reaction is non-spontaneous.

If at a temperature T K , the reaction is spontaneous then-

\Delta H-T\Delta S< 0

or, T> \frac{\Delta H}{\Delta S}

or, T> \frac{10.5\times 10^{3}}{30}

or, T> 350

So at a temperature greater than 350 K, the reaction is spontaneous.

Reaction B: \Delta G=(1.8\times 10^{3})-(-113\times 298)J/mol=35474J/mol

As \Delta G is positive therefore the reaction is non-spontaneous.

If at a temperature T K , the reaction is spontaneous then-

\Delta H-T\Delta S< 0

or, T> \frac{\Delta H}{\Delta S}

or, T> \frac{1.8\times 10^{3}}{-113}

or, T> -16

So at a temperature greater than -16 K, the reaction is spontaneous.

3 0
2 years ago
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