Answer: acetone molecule ( CH₃-CO-CH₃)
Explanation:
1) Acetone is CH₃-CO-CH₃
2) That is a molecule (build up of covalent bonds).
3) When dissolved, covalent bonded compounds remain as separate molecules, then it is said that the major species present in the solution is the molecule. The molecules of acetone are surrounded (sovated) by the molecules of water.
This as opposed to the case of ionic compounds that ionize. When a compound as NaCl dissolves in water, it ionizes completely, so the major speceies are not NaCl formulas, but the ions Na⁺ and Cl⁻, not molecules.
That leads to the answer: the major species present when acetone is dissolved in water is the molecules of acetone (you do not need to state the fact that the molecules of water are part of the solution, because that is not the target of the question).
Answer:2kg
Explanation:
Mass =?
Acceleration = 3.0 m/s2
Force = 6.0N
Force = Mass x Acceleration
6 = Mass x 3
Mass =6/3 = 2Kg
Answer:
3.4 × 10²³ molecules of CBr₄
Explanation:
Given data:
Mass of CBr₄ = 189 g
Number of molecules = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass / molar mass
Number of moles = 189 g/ 331.63 g/mol
Number of moles = 0.6 mol
Now the given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
Foe 0.6 moles of CBr₄:
0.6 mol × 6.022 × 10²³ molecules of CBr₄ / 1 mol
3.4 × 10²³ molecules of CBr₄
62 g of water are vaporized and the energy required is 2.4 kJ/g
So 62g x 2.4 kJ/g = 148.8 kJ or 148,800 Joules
Q = mCΔT
Q is energy in joules, m is mass of water, C is the specific heat, delta T is change in temp
148,800 = m(4.18)(41 - 19) = 1618g or 1.6 kg of water
