We know that the molar mass of N is 14 and O is 16,
therefore the molar mass of N2O is:
molar mass N2O = 14 * 2 + 16 = 44 g/mol
The number of moles:
moles N2O = 0.187 / 44
moles N2O = 0.00425 mol
There are 2 moles of N per 1 mole of N2O hence:
moles N = 0.00425mol * 2
<span>moles N = 0.0085 mol</span>
These are both on the right side of the periodic table, so they bond covalently.The name would be TETRAphosphorous OCTAbromide. Tetra because there are 4 phosphorus molecules, and octa because there re 8 bromine molecules
Hope that helps!
The reaction is (a reação é)
(C6H4(OH)2(aq) + H2O2(aq) --> C6H4O2(aq) + H2O(L) ........(i)
The other reaction given are (A outra reação dada é)
C6H4(OH)2(aq) ---> C6H4(OH)2(aq) + H2(g) .......(ii) ΔH = 177 kJ
2H2O2(aq) ----> 2H2O(l) + O2(g) ..................................(iii) ΔH = -189.3
2H2(g) + O2(g) ----> 2H2O (l) .....................................(iv) ΔH =-572 kJ
We can obtain equation (i) from equation (ii), (iii) and (iv) as
[Podemos obter a equação (i) da equação (ii), (iii) e (iv) como]
equation (i) = equation (ii) + 0.5 X equation (iii) + 0.5 X equation (iv)
[equação (i) = equação (ii) + 0.5 X equação (iii) + 0.5 X equação (iv)]
So ΔH1 = ΔH(ii) + 0.5 X ΔH(iii) + 0.5 X ΔH(iv)
= 177 + 0.5 X (-189.3) + 0.5 X(-572) = -203.65 kJ
