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tino4ka555 [31]
1 year ago
9

A. what are the noble gases? b. what is a noble-gas configuration? c. how does noble-gas notation simplify writing an atom's ele

ctron configuration?​
Chemistry
1 answer:
mamaluj [8]1 year ago
5 0
A. Noble gases are the chemical elements in group 18 of the periodic table. 
B. Noble gas configuration is the electron configuration of noble gases. 
C. Noble gases abbreviates large portions of the configuration. 
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Marcie is hiking in the mountains and she discovers an interesting shiny rock.As she picks it up she wonders whether it could be
pogonyaev

Answer:

Marcie pick up a rock

Explanation:

A rock is a natural occuring no living thing that has a definite structure from the physical characteristics Marcie saw in the rock she picked it tends to rock because unlike minerals rocks has definite structure.

3 0
2 years ago
Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca
lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=-0.23-0.77=-1.0V

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

3 0
2 years ago
What is the name for molecular compound N4O8?
zmey [24]
Tetranitrogen octoxide
8 0
2 years ago
Read 2 more answers
N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t
son4ous [18]

Answer : The mole fraction of nitrogen will be 0.4615.


Explanation : When nitrogen (N_{2})and hydrogen (H_{2})are mixed, the mole ratio becomes 1 : 1.5,


Now we know that (H_{2}) is acting as a limiting agent.


So at the time of when 0.4 moles of (NH_{3}) is been formed it requires 0.4 moles of (N_{2}) and 3.4 moles of (H_{2})


So, we find the the remaining (N_{2}) will be 0.6 and

(H_{2}) will be 0.3 mole present in mixture.


So, the mole fraction of (N_{2}) becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615

8 0
2 years ago
Read 2 more answers
Find the molarity of 750 ml solution containing 346 g of potassium nitrate
Zinaida [17]
Given mass of KNO₃=346g
Molar mass of KNO₃=(39.098)+(14)+(15.99*3)=101.068gmol⁻¹
Volume of Solution=750ml=0.75dm³

Molarity=(mass of solute/molar mass of solute)*(1/volume of sol. in dm³)
            =(346/101.068)*(1/0.75)
            =4.56 mol dm⁻³
5 0
2 years ago
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