Answer: Cu
Explanation: It is Cu because the origin of the word Copper comes from the latin word "Cuprum".
Answer:
Phosphorous has the smallest atomic size.
Explanation:
As we know these elements belong to same period means there valence shell is the same. So moving from left to right along the period the shell number remains constant but the number of protons and electrons increases. So, due to increase in number of protons the nuclear charge increases hence attracts the valence electrons more effectively resulting in the decrease of atomic size.
Elements and their atomic radius are as follow,
<span><span>Magnesium 0.160 nm
</span><span>
Aluminium 0.130 nm
</span><span>
Silicon 0.118 nm
</span><span>
Phosphorus <span>0.110 nm</span></span></span>
<u>Answer:</u> The value of
for the reaction at 690 K is 0.05
<u>Explanation:</u>
We are given:
Initial pressure of
= 1.0 atm
Total pressure at equilibrium = 1.2 atm
The chemical equation for the decomposition of phosgene follows:

Initial: 1 - -
At eqllm: 1-x x x
We are given:
Total pressure at equilibrium = [(1 - x) + x+ x]
So, the equation becomes:
![[(1 - x) + x+ x]=1.2\\\\x=0.2atm](https://tex.z-dn.net/?f=%5B%281%20-%20x%29%20%2B%20x%2B%20x%5D%3D1.2%5C%5C%5C%5Cx%3D0.2atm)
The expression for
for above equation follows:


Putting values in above equation, we get:

Hence, the value of
for the reaction at 690 K is 0.05
Use the formula, Q= mcT
Q= heat
m= mass= 1.900Kg= 1.900 x 10^3 grams
c= specific heat= 3.21
T= 4.542 K
Q= (1.900 x10^3g)(3.21)(4.542K)= 14.6 Joules.
Answer:
a

b

Explanation:
From the question we are told that
The pressure of compressed gas is 
The temperature is 
Generally the perfect gas equation is mathematically represented as

substituting 0.08206 L-atm/mol-K for R and 1 mole for n
We have that


Generally the van der Waals equation is mathematically represented as
![nRT = [P + \frac{n^2 * a }{V^2 } ][V - nb]](https://tex.z-dn.net/?f=nRT%20%20%3D%20%20%5BP%20%2B%20%5Cfrac%7Bn%5E2%20%2A%20a%20%7D%7BV%5E2%20%7D%20%5D%5BV%20-%20nb%5D)
=>![1 * 0.08206 *298 = [197.4 + \frac{1^2 * 1.364}{V^2 } ][V - 1 * 3.19 * 10^{-2}]](https://tex.z-dn.net/?f=1%20%2A%20%200.08206%20%2A298%20%20%3D%20%20%5B197.4%20%2B%20%5Cfrac%7B1%5E2%20%2A%20%201.364%7D%7BV%5E2%20%7D%20%5D%5BV%20-%201%20%2A%203.19%20%2A%2010%5E%7B-2%7D%5D)
=> 