The source of these two nitrogen atoms are ammonia (NH₃) from <span>nitrogen compounds (mostly metabolism of amino acids) through which excess nitrogen is eliminated from organisms. This process is called urea cycle, which extracted </span>nitrogenous wastes.
The liver<span> forms it by combining two </span>ammonia<span> molecules</span><span> with a </span>carbon dioxide<span> </span><span>molecule.</span><span />
<u>Answer:</u> The electronic configuration of the elements are written below.
<u>Explanation:</u>
Electronic configuration is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom is determined by the atomic number of that atom.
For the given options:
- <u>Option a:</u> Carbon (C)
Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.
The electronic configuration of carbon is 
- <u>Option b:</u> Phosphorus (P)
Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.
The electronic configuration of phosphorus is 
- <u>Option c:</u> Vanadium (V)
Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.
The electronic configuration of vanadium is 
- <u>Option d:</u> Antimony (Sb)
Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.
The electronic configuration of antimony is 
- <u>Option e:</u> Samarium (Sm)
Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.
The electronic configuration of samarium is 
Hence, the electronic configuration of the elements are written above.
Let's write the reaction first.
HCl + H₂O ---> H₃O⁺ + Cl⁻
These reaction has two reactants, either the proton donor or the proton acceptor. Water is amphoteric, meaning it can act as an acid or base. Since HCl is an acid, then water in this reaction acts as a base.
1. The proton donor is HCl because it donates H+ to water which yields a hydronium ion, H₃O⁺.
2. The proton acceptor is water.
In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.
According to the law of the conservation of energy, energy cannot be destroyed or created. It is can only be transformed from one form to another.
Reactions of Ethyl-3-pentenoate with all given reagents are given below.
Reaction with H₂ / Pd:
The non-polar double bond present in Ethyl-3-pentenoate is reduced to saturated chain. This reagent can not reduce the carbonyl group.
Reaction with NaBH₄: Sodium Borohydride is a weak reducing agent at compared to LiAlH₄. It can only reduce aldehydes and Ketones to corresponding alcohols.
Reaction with LiAlH₄: Lithium Aluminium hydride is a strong reducing agent. It can reduce all types of carbonyl compounds to corresponding alcohols, But, it can not reduce non-polar double bonds like alkenes and alkynes.
Result: The correct answer is
Option-A (Highlighted RED below).