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LenaWriter [7]
2 years ago
12

Moles of C2H6 in 3.75x10 ^23 molecules of C2H6

Chemistry
2 answers:
Blizzard [7]2 years ago
5 0

Answer : The number of moles of C_2H_6 is, 0.622 moles

Solution :

As we know that,

1 mole contains 6.022\times 10^{23} number of molecules.

As, 6.022\times 10^{23} number of molecules of C_2H_6 present in 1 mole of C_2H_6

So, 3.75\times 10^{23} number of molecules of C_2H_6 present in \frac{3.75\times 10^{23}}{6.022\times 10^{23}}=0.622 mole of C_2H_6

Therefore, the number of moles of C_2H_6 is, 0.622 moles

Elan Coil [88]2 years ago
3 0
To determine the moles of C2H6 from the number of molecules, we use the avogadro's number to relate moles into molecules. From avogadro's number, 1 mol is equal to 6.022x10^23 molecules. 

<span> 3.75x10 ^23 molecules C2H6 (1 mol / 6.022x10^23 molecules ) = 0.6227 mol C2H6

Hope this answers the question.</span>
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In the third period of the periodic table sodium is followed by magnesium aluminum silicon and phosphorus which of these element
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<span><span>Magnesium          0.160 nm
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2 years ago
COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at
mestny [16]

<u>Answer:</u> The value of K_p for the reaction at 690 K is 0.05

<u>Explanation:</u>

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Total pressure at equilibrium = 1.2 atm

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                  COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial:            1                    -         -

At eqllm:       1-x                 x        x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

[(1 - x) + x+ x]=1.2\\\\x=0.2atm

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K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

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Putting values in above equation, we get:

K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05

Hence, the value of K_p for the reaction at 690 K is 0.05

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A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s
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7 0
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Read 2 more answers
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mars1129 [50]

Answer:

a

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b

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Explanation:

From the question we are told that

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We have that

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Generally the van der Waals equation is mathematically represented as

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=>    V  =  0.112 \  Liters

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