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ale4655 [162]
2 years ago
10

What is [h3o ] in a solution of 0.25 m ch3co2h and 0.030 m nach3co2?

Chemistry
1 answer:
Brilliant_brown [7]2 years ago
4 0
Hello!

To determine [H₃O⁺], we need to apply the Henderson-Hasselback equation, since this is a case of an acid and its conjugate base:

pH=pKa+log( \frac{[A^{-}] }{[HA]} )

pH=4,76+log( \frac{0,030M}{0,25M} ) \\  \\ pH=3,84

Now, we use the definition of pH and clear [H₃O⁺] from there:

pH=-log[H_3O^{+}]

[H_3O^{+}] = 10^{-pH} =10^{-3,84}=0,00014 M

So, the [H₃O⁺] concentration is 0,00014 M

Have a nice day!
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Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom
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Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

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Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

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Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

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2 years ago
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1.216mol

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The molar mass of C₄H₁₀ is (12 x4)+ (1x 10) = 48 + 10 = 58g

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70.7 grams = 70.7 x 0.017205129881525  = 1.216mol

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