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miv72 [106K]
2 years ago
12

During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/mi

n 227 g/min 908 g/min 13,600 g/min
Chemistry
1 answer:
Eduardwww [97]2 years ago
3 0
The solution for this problem would be:
The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min 
So solving for the rate will be mass over t = m/t = 227/0.25 = 908 g/min would be the answer for this problem.
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FeSO₄*7H₂O(s) = FeSO₄(s) + 7H₂O(g)

M(FeSO₄*7H₂O)=278.0 g/mol
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m(FeSO₄*7H₂O)/M(FeSO₄*7H₂O)=m(FeSO₄)/M(FeSO₄)

m(FeSO₄)=M(FeSO₄)m(FeSO₄*7H₂O)/M(FeSO₄*7H₂O)

m(FeSO₄)=151.9*100.0/278.0=54.6 g

m(FeSO₄)=54.6 g


4 0
2 years ago
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Andreyy89
M= #moles / L
 
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1 year ago
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Answer:

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